Question

How many atoms of copper will react with 33.9 L of nitrogen stp to produce copper nitride

Answer 1

Hello user


Answer: 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.

I hope I helped 
-Chris

Answer 2

Answer : The number of atoms of copper will be, $54.67\times 10^{23}$

Solution :

As we know that 1 mole contains $6.022\times 10^{23}$ number of atoms

And,

At STP, 1 mole contains 22.4 liter volume of gas

First we have to calculate the moles of copper.

The balanced chemical reaction will be,

$6Cu+N_2\rightarrow 2Cu_3N$

From the balanced chemical reaction we conclude that, 1 mole of nitrogen gas react with 6 moles of copper.

As, 22.4 L volume contains 6 moles of copper

So, 33.9 L volume contains $\frac{6}{22.4}\times 33.9=9.08$ moles of copper

Now we have to calculate the number of atoms of copper.

As, 1 mole of copper contains $6.022\times 10^{23}$ number of copper atoms

So, 9.08 moles of copper contains $9.08\times (6.022\times 10^{23})=54.67\times 10^{23}$ number of copper atoms

Therefore, the number of atoms of copper will be, $54.67\times 10^{23}$