Molybdenum Arsenide
I think that’s right but not %100 sure
<span>n = 5 shell=50</span>
<span>n = 2 shell=8</span>
<span>n = 2, l = 0 subshell=2</span>
<span>n = 2, l = 1 subshell=6</span>
<span><span>3d subshell=</span>10</span>
<span>2s subshell=2</span>
<span><span>5f subshell=14</span></span><span><span> sorry if I'm late I just did this! hope it helps..</span></span>
Answer:
0.1M solution of NaOH
Explanation:
1 mole of NaOH - 40g
? moles - 1 g = 1/40 = 0.025 moles.
Molarity of 1.00g of NaOH in 0.25L (250 mL) = no. of moles/volume
= 0.025/0.25
= 0.1M.
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
1, Read the entire lab procedure through and make sure it is understandable. 2, Put on safety goggles and an apron. 3, Check the flask for chips and cracks. 4, <span> Use heat-resistant gloves or tongs to swirl the flask.</span>