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2 years ago

Calculate the maturity value for an interest-bearing note of $28,500 for 118 days at 8%

1 answer:

8 0

Hi I'm new so but what you have to do is add the money up than you should add it with the 118 days because i just did this quiz and i got an 100% all the way and plz put this the bralnl' yest
p.s your wolcome

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A software store has put some of its inventory on sale. Games are marked down by 15%, and security programs are marked down by 1

Katyanochek1 [597]

Answer:

Option D. $\$11.34$

Step-by-step explanation:

Let

x -----> the original price of one game

y ----> the original price of one security programs

Remember that

$100\%-15\%=85\%=85\100=0.85$

$100\%-18\%=82\%=82\100=0.82$

The total pay with discount is

$\$35.70+\$22.96=\$58.66$

we have that

$0.85(2x)=35.70\\1.70x=35.70\\x=\$21$

$0.82y=22.96\\y=\$28$

Find the total pay without discount

$2x+y=2(21)+28=\$70$

The amount saved is the difference

$\$70-\$58.66=\$11.34$

5 0

2 years ago

Read 2 more answers

Kayleigh babysat for 11 hours this week. That was 5 fewer than 2/3 as many hours as she babysat last week, h. Write an equation

lukranit [14]

Answer: The answer is $\textup{x}=\dfrac{2}{3}\textup{h}-5.$

Step-by-step explanation: Given that Kayleigh babysat for 11 hours the present week. Also, this was 5 less than two-third of the number of hours she babysat last week, which is represented by 'h'.

We are to write an equation to represent the number of hours she babysat each week.

So, for that, let 'x' be the number of hours she babysat this week. Then, according to the question, we can write

$\textup{x}=\dfrac{2}{3}\textup{h}-5.$

Also, it is given that

$\textup{x}=11.$

Therefore,

$11=\dfrac{2}{3}\textup{h}-5\\\\\Rightarrow \dfrac{2}{3}\textup{h}=16\\\\\Rightarrow \textup{h}=24.$

Hence, using the above relation, we can find the number oh hours Keyleigh babysat each week.

Thus, the required equation is

$\textup{x}=\dfrac{2}{3}\textup{h}-5,$

where, 'x' and 'h' are the number of hours she sat this week and last week respectively.

4 0

2 years ago

Which classification best represents a triangle with side lengths 6 cm, 10 cm, and 12 cm? acute, because 62 + 102 < 122 acute

maw [93]

The Pythagoras theorem states that
the sum of squares of the shorter sides (legs) of a right triangle equals the square of the third side.

A corollary from the same theorem helps us solve this problem:
If the sum of the squares of the shorter sides of a triangle is greater than the square of the third side, the included angle is acute. ..... (case 1)
Conversely, if the sum of the squares of the shorter sides of a triangle is less than the square of the third side, the triangle is obtuse. .....(case 2)

Here we have
6^2+10^2 = 36+100=136 <12^2=144
Therefore case 2 applies, and the triangle is obtuse.

7 0

2 years ago

Read 2 more answers

A scientist looks at a bacterium and a virus in a lab. The bacterium has a diameter of mc020-1.jpg meters. The virus has a diame

Reil [10]

You can divide the two values A = diameter of bacterium B = diameter of virus A/B = (10^(-6))/(10^(-7)) A/B = 10^(-6-(-7)) A/B = 10^(-6+7) A/B = 10^(1) A/B = 10 Since the ratio of the two diameters is 10, this means that the diameter of the bacterium is 10 times greater than that of the virus.

6 0

2 years ago

A modem transmits over an error-prone channel, so it repeats every "0" or "1" bit transmission five times. We call each such gro

Gemiola [76]

Answer:

0.00111

Step-by-step explanation:

Since the modem receiver takes a majority vote of the five

received bits to estimate the input signal, it will only make a wrong decision if 3, 4 or 5 of the 5 bits received are wrong.

Given that the channel changes an input bit to its complement with probability p =1/10 and it does so independently of its treatment of other input bits, the probability of changing 3 bits out of five is 0.1*0.1*0.1 = 0.001, of changing 4 is 0.0001 and of changing 5 is 0.00001

So, the probability that the modem makes a wrong decision is 0.001+0.0001+0.00001 = 0.00111

5 0

2 years ago