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2 years ago

How many moles are there in 25.0 grams of KMnO4

2 answers:

8 0

The answer is 158.033949. I assume you are converting between grams KMnO4 and mole. This compound is also known as Potassium Permanganate.

Ksju [112]2 years ago

7 0

Answer:

There are 0.158 moles of $KMnO_{4}$ in 25.0 g of $KMnO_{4}$

Explanation:

Molar mass of $KMnO_{4}$ is 158.034 g/mol

So, mass of 1 mol of $KMnO_{4}$ is 158.034 g . Therefore number of moles of $KMnO_{4}$ in 25.0 g sample is $\frac{25.0}{158.034}$ moles or 0.158 moles.

It should be remembered that, number of moles= $\frac{mass}{molar mass}$

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To save time you can approximate the initial volume of water to ±1 mL and the initial mass of the solid to ±1 g. For example, if

WARRIOR [948]

Answer:

20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

Explanation:

Since the density formula is mass divided volume, you can calculate the density of each of the components of the group and see which of all the groups are equal

In the group

density Ag=20.2 g silver/21.6ml H2O=0.9352g/ml

density Cu=20.2 g copper/21.6ml H2O=0.9352 g/ml

6 0

2 years ago

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A mixture of carbon dioxide and an unknown gas was allowed to effuse from a container. The carbon dioxide took 1.25 times as lon

Aleks04 [339]

Answer:

Explanation:

From Graham's law, time taken to diffuse is directly proportional to the molecular mass of the gases. For two different gases.

t1/t2=√m1/m2

Since gas 1 diffuse 1.25 times as slowly as gas 2 and gas 1 is CO2 with m as 44g

1.25/1=√44/m2

Therefore m2=28g CO

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2 years ago

Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce

sergeinik [125]

Answer:

The empirical formula is = $C_4H_8O$

The formula of Valproic acid = $C_8H_{16}O_2$

Explanation:

Mass of water obtained = 0.166 g

Molar mass of water = 18 g/mol

Moles of $H_2O$ = 0.166 g /18 g/mol = 0.00922 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 0.00922 = 0.01844 moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 0.01844 x 1.008 = 0.018588 g

Mass of carbon dioxide obtained = 0.403 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of $CO_2$ = 0.403 g /44.01 g/mol = 0.009157 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 0.009157 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 0.009157 x 12.0107 = 0.11 g

Given that the Valproic acid only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C - Mass of H

Mass of the sample = 0.165 g

Mass of O in sample = 0.165 - 0.11 - 0.018588 = 0.036412 g

Molar mass of O = 15.999 g/mol

Moles of O = 0.036412 / 15.999 = 0.002276 moles

Taking the simplest ratio for H, O and C as:

0.01844 : 0.002276 : 0.009157

= 8 : 1 : 4

The empirical formula is = $C_4H_8O$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 4×12 + 8×1 + 16= 72 g/mol

Molar mass = 144 g/mol

So,

Molecular mass = n × Empirical mass

144 = n × 72

⇒ n = 2

The formula of Valproic acid = $C_8H_{16}O_2$

7 0

2 years ago

93.2 mL of a 2.03 M potassium fluoride (KF) solution

Marrrta [24]

Answer:

1.98 M

Explanation:

Given data

Initial volume (V₁): 93.2 mL

Initial concentration (C₁): 2.03 M

Volume of water added: 3.92 L

Step 1: Convert V₁ to liters

We will use the relationship 1 L = 1000 mL.

$93.2mL \times \frac{1L}{1000mL} = 0.0932 L$

Step 2: Calculate the final volume (V₂)

The final volume is the sum of the initial volume and the volume of water.

$V_2 = 0.0932L + 3.92 L = 4.01L$

Step 3: Calculate the final concentration (C₂)

We will use the dilution rule.

$C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M$

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2 years ago

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Daphne is a pilot for a package delivery service. As her plane takes off and travels away from the Earth’s surface, its gravitat

Lubov Fominskaja [6]

Answer:

its height relative to some reference point, its mass, and the strength of the gravitational field

Explanation:

Gravitational energy is the potential energy associated with gravitational force, such as elevating objects against the Earth’s gravity. The potential energy due to elevated positions is called gravitational potential energy.

The factors that affect an object’s gravitational potential energy are the following; its height relative to some reference point, its mass, and the strength of the gravitational field it is in. For instance, consider a wallet lying on a table, it has less gravitational potential energy than the same wallet lying on top of a taller cupboard, and yet lesser gravitational potential energy than a heavier wallet lying on the same table.

If an object lies at a certain height above the Moon’s surface, it has less gravitational potential energy than the same object lying at the same height above the Earth’s surface because the Moon’s gravitational force is weaker.

5 0

2 years ago