We use the z statistic:
z = (x – u) / s
But first let us calculate the standard deviation s,
sample x and mean u.
s = sqrt (n p q)
s = sqrt (112 * 0.77 * (1 – 0.77))
s = 4.45
x = 0.81 * 112 = 90.72
u = 0.77 * 112 = 86.24
So the z score is:
z = (90.72 – 86.24) / 4.45
z = 1.00
From the standard tables, the P value at z = 1.00 using
right tailed test is:
<span>P = 0.1587 = 15.87%</span>
The sum of two consecutive even integers is a+(a+2) and divided by four is
(a+(a+2))/4 = 189.5
(2a+2)/4 = 189.5
2a+2 = 189.5 * 4
2a+2 = 758
2a = 758 - 2
2a = 756
a = 756/2 = 378
first number is a = 378
second number is a+2 = 378+2 = 380
Answer:
5m/s;
6 seconds
Step-by-step explanation:
Given the following :
Initial position = 30 m below
He climbed at a constant rate, and was 7.5 m below after 4.5 s.
Distance climbed or covered in 4.5 seconds :
(Initial position - current position)
(30 - 7. 5)m = 22.5 meters
Using the relation:
Speed = distance covered / time taken
Therefore,
Shota's speed = 22.5m / 4.5s = 5m/s
Time taken to reach edge of volcano :
Distance left to cover = 7.5m
Speed = 5m/s
Time required to cover remaining distance :
= distance / speed
= (7.5m ÷ 5m/s) = 1.5s
Total time to reach edge :
(4.5 + 1.5)s = 6 seconds
Answer:
Step-by-step explanation:
The calculation of the value of p minimizes is shown below:-
We will assume the probability of coming heads be p
p(H) = p
p(T) = 1 - P
Now, H and T are only outcomes of flipping a coin
So,
P(TTH) = (1 - P) = (1 - P) (1 - P) P
= (1 + P^2 - 2 P) P
= P^3 - 2P^2 + P
In order to less N,TTH
we need to increase P(TTH)
The equation will be
3P^2 - 4P + 1 = 0
(3P - 1) (P - 1) = 0
P = 1 and 1 ÷ 3
For P(TTH) to be maximum
= 6P - 4
and
(6P - 4) is negative which is for
