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ser-zykov [4K]
2 years ago
9

A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this

reaction to be ______ and _____.
Chemistry
2 answers:
SpyIntel [72]2 years ago
8 0
A double replacement is when the reactants switch with their opposite charge. For example, AB + CD = AD + BC.

In this case the given is K2SO4 + Pb(NO3)2 = ____ + ____

The answers is PbSO4 and KNO3 would expect the products of this reaction.
ella [17]2 years ago
6 0

Answer:

The products are PbSO₄ and KNO₃

Explanation:

Double replacement reaction, also called double displacement reaction is a type of reaction in which the two reactants exchange there cations or anions as represented below

AB + CD ⇒ AD + CB

The reaction provided in the question is expected to produce the products shown below

K₂SO₄ + Pb(NO₃)₂ ⇒ PbSO₄ + 2KNO₃

As you can see from the equation above, both potassium (K) in K₂SO₄ and lead (Pb) in Pb(NO₃)₂ exchanged there positions hence the reaction is a double displacement which formed PbSO₄ and KNO₃

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consider the reaction between sulfite and a metal anion, X2-, to form the metal, X, and thiosulfate: 2 X2-(aq) + 2 SO32- + 3 H2O
Dafna11 [192]

Answer:

E_{red}^{0} for X is -1.20 V

Explanation:

Oxidation: 2\times[X^{2-}(aq.)-2e^{-}\rightarrow X(s)]

reduction: 2SO_{3}^{2-}(aq.)+3H_{2}O(l)+4e^{-}\rightarrow S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

---------------------------------------------------------------------------------------------------

overall:2X^{2-}(aq.)+2SO_{3}^{2-}(aq.)+3H_{2}O(l)\rightarrow 2X(s)+S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

So, E_{cell}^{0}=E_{red}^{0}(SO_{3}^{2-}\mid S_{2}O_{3}^{2-})-E_{red}^{0}(X\mid X^{2-})

or, 0.63=-0.57-E_{red}^{0}(X\mid X^{2-})

or, E_{red}^{0}(X\mid X^{2-})= -1.20

So, E_{red}^{0} for X is -1.20 V

8 0
2 years ago
Read 2 more answers
Write a balanced equation for the transmutation that occurs when a scandium-48 nucleus undergoes beta decay.
Tju [1.3M]

Answer:

A scandium-48 nucleus undergoes beta-minus decay to produce a titanium-48 nucleus.

\rm ^{48}_{21}Sc \to ^{48}_{22}Ti + ^{\phantom{1}\,0}_{-1}e^{-} + \bar{\mathnormal{v}}_e.

Explanation:

There are two types of beta decay modes: beta-minus and beta-plus.

In both decay modes, the mass number of the nucleus stays the same.

However, in a beta-minus decay, the atomic number of the nucleus increases by one. In a beta-plus decay, the atomic number decreases by one.

Each beta-minus decay releases one electron and one electron antineutrino. Each beta-plus decay releases one positron and one electron neutrino.

Look up the atomic number and relative atomic mass for the element scandium.

  • The atomic number of \rm Sc is 21.
  • The relative atomic mass of \rm Sc is approximately 45.0.

This question did not specify whether the decay here is beta-plus or a beta-minus. However, the relative atomic mass of this element can give a rough estimate of the mode of decay.

Each element (e.g, \rm Sc) can have multiple isotopes. These isotopes differ in mass. The relative atomic mass of an element is an average  across all isotopes of this element. This mass is weighted based on the relative abundance of the isotopes. Its value should be closest to the most stable (and hence the most abundant) isotope.

The mass number of scandium-48 is significantly larger than the relative atomic mass of this element. In other words, this isotope contains more neutrons than isotopes that are more stable. There's a tendency for that neutron to convert to a proton- by beta-minus decay, for example.

The atomic number of the nucleus will increase by 1. 21 + 1 = 22. That corresponds to titanium. The mass number stays the same at 48. Hence the daughter nucleus would be titanium-48. Note that two other particles: one electron and one electron \rm e^{-} and one antineutrino \bar{v}_{\text{e}} (note the bar.) The neutrino helps balance the lepton number of this reaction.

6 0
2 years ago
Perform the following
Ghella [55]

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

4 0
2 years ago
DNA can be replicated through an in vivo mechanism or a polymerase chain reaction (PCR) mechanism. Match each description to the
umka2103 [35]

Complete question from other source attached

Answer:

Explanation:

Catalyzed by DNA polymerase - both. DNA polymerase catalyzes DNA replication in the cell. However, purified versions of the enzyme are also used to synthesise DNA as part of PCR reactions

involves leading strand synthesis only - PCR. In PCR, lagging strand synthesis is not carried out because the DNA is denatured (rendered single stranded). Therefore, each strand is replicated independently by leading strand synthesis

duplicates a small fragment of the genome - PCR. Usually, to carry out PCR, small sequences called primers are used that specify the region of DNA to be replicated

duplicates the entire genome - in vivo replication - when the DNA is replicated in vivo, the entire genome is replicated. This is carried out prior to cell division so that two daughter cells can each inherit a copy of the entire genome

7 0
2 years ago
Match each set of quantum numbers to the correct subshell description by typing in the correct number.
Mice21 [21]
The location of the valence electron or the outermost electron is expressed in quantum numbers. There are five quantum numbers: prinicipal (n), angular momentum (l), magnetic (ms) and magnetic spin (ms) quantum numbers. This is based on Bohr's atomic model where electrons orbit around the nucleus. These electrons are in the orbitals with specific energy levels. Starting from energy level 1 that is closest to the nucleus, the energy level decreases to 2, 3, 4, 5, 6, and 7. These energy level numbers represent the principal quantum number. Within each orbital also contains subshell. From increasing to decreasing order, these subshells are the s, p, d and f subshells. These subshells represent the angular momentum quantum numer. Specifically, s=0, p=1, d=2 and f=3. Therefore, if the electron is in the orbital 5p, the quantum number would be: 5, 1. Applying these to the choices, the correct pairing would be:

2p: n=2. l=1
3d: n=3, l=2
2s: n=2. l=0
4f:  n=4. l=3
1s: n=1, l=0
8 0
2 years ago
Read 2 more answers
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