A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west. what impulse is required to decrease the speed of t
2 answers:
The impulse required to decrease the speed of the boat is equal to the variation of momentum of the boat:
where
m=225 kg is the mass of the boat
is the variation of velocity of the boat
By substituting the numbers into the first equation, we find the impulse:
and the negative sign means the direction of the impulse is against the direction of motion of the boat.
where
m=225 kg is the mass of the boat
By substituting the numbers into the first equation, we find the impulse:
and the negative sign means the direction of the impulse is against the direction of motion of the boat.
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P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
Answer:
Explanation: Angular velocity is the number of revolutions made per unit time.
We convert the number of revolutions to radians and the time given in seconds to minutes,
Given;
Also,
60s = 1 min
hence
We now divide the number of revolution in radians by the time in minutes.
Answer:
Weight W = 392.4 N
Density = 784.31
Specific gravity S = 0.78431
Force required F = 10 N
Explanation:
Given data
Mass (m) = 40 kg
Volume (V) = 0.051
Weight W = m × g
⇒ W = 40 × 9.81
⇒ W = 392.4 N
This is the weight of the methanol.
Density =
⇒ =
⇒ = 784.31
This is the density of the methanol.
Specific gravity (S) =
⇒
⇒ S = 0.78431
This is the specific gravity of the methanol.
Force needed to accelerate this tank F = ma
⇒ F = 40 × 0.25
⇒ F = 10 N
This is the force required to accelerate the tank.