Answer:
The program to this question as follows:
Program:
#include<iostream> //include header file.
using namespace std; //using name space.
int main() //main function.
{
int n,i,key; //define variable.
int a[n]; //define array
cout<<"Enter size of array :"; //message.
cin>>n; //input number from user.
cout<<"Enter array elements :"; //message
for(i = 0;i<n;i++) //loop
{
cin>>a[i]; //input array elements
}
cout<<"Enter a number:"; //message
cin>>key; //input number.
for(i = 0;i<n;i++) //loop
{
if(a[i]<=key) //if block
{
cout<<a[i]<<"\n "; //print array elements
}
}
return 0;
}
Output:
Enter size of array :7
Enter array elements :5
50
50
75
100
200
140
Enter a number:100
5
50
50
75
100
Explanation:
The description of the above program as follows:
- In this program first, we include a header file and define the main method in method we define variables and array that are "n, i, key and a[]". In this function, all variable data type is "integer".
- The variable n is used for the size of array and variable i use in the loop and the key variable is used for comparing array elements. Then we use an array that is "a[]" in the array, we use the for loop to insert elements form user input.
- Then we define a loop that uses a conditional statement in if block we check that array elements is less than and equal to a key variable. If this value is true so, we will print the remaining elements.
Answer:
Explanation:
Assuming the spoofed 1.2.3.4, it will be sent out ARP to a router that is alive and get it MAC. Then the spoofed packet will be able to be sent out. If A spoofed 10.0.2.30, because it is a local address, it will send an ARP to the machine for been able to get the MAC. But, the IP address 10.0.2.30 is not original making it to be fake, so it will not replay to A, for this reason the spoofed packet cannot be sent out.
Answer:
<em>Ethernet cables, Network Adapters, Modem, Routers, Switches.</em>
Explanation:
<em>The devices that are required in setting up a wired network for the 5 computer comprises of the following devices </em>
- <em>Ethernet Cables</em>
- <em>Network Adapters</em>
- <em>Modem/Router</em>
- <em>Network Switch</em>
<em>Ethernet cables: They are called network cables or RJ-45 cables used to in connecting two or more computers together. it has different categories called, the untwisted pair and twisted pair Ethernet, with a speed from 10-1000</em>
<em>Network Adapters : This adapters allows a computer device to connect and interface with a network computer</em>
<em>Modem/Routers : A router is a device that that sits in the middle between your local computers and modems. it takes receives information or gets information from the modem and delivers it to the computer</em>
<em>Network switch: it connects more than two computers together to a network and share data among themselves and other devices on the network</em>
The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.
Further Explanation:
There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.
There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.
Learn more about Windows at brainly.com/question/1705478
#LearnwithBrainly
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
