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Artyom0805 [142]
2 years ago
6

Which native windows application allows one to access basic pc settings and controls system info?

Computers and Technology
2 answers:
vlabodo [156]2 years ago
7 0
As far as windows 7 and below it was control panel, but in windows 8 and higher, microsoft added, a new app which was called settings, control panel was still there but with a few features removed
NikAS [45]2 years ago
7 0

Answer:

The native windows application that allows one to access basic pc settings and controls system info is:

The system tab.

Explanation:

Even though the windows control panel lets you know and control with deepness all of the operative system hardware. The system tab is the one that allows you to know basic pc settings that are essential to understand the full structure of the machine. An example of them is RAM, CPU, OS, and sometimes the graphics card.

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Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c
boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

\lambda (N) = \ lcm( \lambda  (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)  where \lambda is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from 1and gcd(E,  \lambda (N) ) = 1; that is E \ \ and  \ \ \lambda (N).  D was its complex number equivalent to E (modulo \lambda (N) ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo \lambda (N) ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and \lambda (N) will also be confined as they can be used in measuring D. The Euler totient operates \varphi (N) = (P-1)(Q - 1) however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because \varphi (N), which can always be split into  \lambda (N), and thus any D satisfying DE ≡ 1, it can also satisfy (mod  \lambda (N)). It works because \varphi (N), will always be divided by \varphi (N),. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   \lambda (N) ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   \lambda (N). if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  \lambda (N).

As there are common threads (P− 1) and (Q – 1) which are present throughout the N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1)), it's also possible, if there are any, for all the common factors (P -1) \ \ \ and \ \ (Q - 1)to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module \varphi (N)) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0
2 years ago
Which organization supports professionals who assist families in making informed choices about products and services?
Naily [24]
The organisation that would best aid families and choose the right products to buy would be the American Association of Family and Consumer Sciences. In addition, the institution is primarily composed of home economists wherein these professionals promote efficient consumer consumption of goods.
6 0
2 years ago
Read 2 more answers
Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
Write an if statement that assigns 10,000 to the variable bonus if the value of the variable goodsSold is greater than 500,000.
aev [14]

Answer:

if(goodsSold>500000){

bonus = 10000;

}

Explanation:

A complete Java program that prompts user to enter value for goodsSold is given below:

<em>import java.util.Scanner;</em>

<em>public class num14 {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        System.out.println("Enter goods Sold: ");</em>

<em>        int goodsSold = in.nextInt();</em>

<em>        int bonus =0;</em>

<em>        if(goodsSold>500000){</em>

<em>            bonus=10000;</em>

<em>        }</em>

<em>        System.out.println("You bonus for "+goodsSold+" is "+bonus);</em>

<em>    }</em>

<em>}</em>

3 0
2 years ago
What does Josh Silverman name as the most important aspect of managing finances?
Andre45 [30]

The answer is a the first one

6 0
1 year ago
Read 2 more answers
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