Answer:
height of the water rise in tank is 10ft
Explanation:
Apply the bernoulli's equation between the reservoir surface (1) and siphon exit (2)

-------(1)
substitute 
0ft/s for V₁, 20ft for (z₁ - z₂) and 32.2ft/s² for g in eqn (1)


Applying bernoulli's equation between tank surface (3) and orifice exit (4)

substitute

0ft/s for V₃, h for z₃, 0ft for z₄, 32,2ft/s² for g

At equillibrium Fow rate at point 2 is equal to flow rate at point 4
Q₂ = Q₄
A₂V₂ = A₃V₃
The diameter of the orifice and the siphon are equal , hence there area should be the same
substitute A₂ for A₃
for V₂
for V₄
A₂V₂ = A₃V₃

Therefore ,height of the water rise in tank is 10ft
I know you're probably done with this by now, but the answer is *Lake-Effect Snow*
Answer:
Explanation:
A simple light microscope uses light for imaging of objects where as a transmission electron microscope uses a monochromatic beam of electrons.
This beam is passed by a magnetic field which is very strong and thus act as a lens.
Its resolution of very high which is about 0.2 nanometers because of the separation between two atoms.
Because of this reason its resolution is about 1000 times greater than light microscope.
Answer:
The variation is inversely proportional to the decrease density
Explanation:
This is an exercise where we will use the Archimedes principle that states that the thrust is equal to the weight of the dislodged liquid
B = m g
ρf = m / Vf
m = ρf Vf
B = ρf Vf g
If we use Newton's second law for equilibrium
B - W = 0
B = m g
ρ Vf g = ρb Vb g
ρb / ρf = Vf / Vb (1)
Let's apply this expression to our case
In water
Vf / Vg = 0.90
replace in equation 1
ρb / ρf = 0.90
ρb = ρf 0.90
ρb = 1000 0.90
ρb = 900 kg / m3
Now we change the liquid to one with lower density, let's calculate the volume ratio
Vf / Vg = ρb / ρf
The density of the body (ρb) remains constant if the density of the fluid decreases, as in the denominator the volume fraction increases, whereby the submerged part decreases
The variation is inversely proportional to the decrease density
<span>Based
on Newton's law of universal gravitation, the equation for the
gravitational force exerted by an object on another object is given by:
F = Gm1m2/(r^2)
where G is the universal gravitational constant, F is the gravitational
force exerted, m1 is the mass of the first object, m2 is the mass of the
second object, and r is the separation distance between the two
objects.
If the mass of both objects were doubled, then we would have: m1' * m2' =
(2m1) * (2m2) = 4m1m2. Assuming r stays constant (G is a constant so
that won't change anyway), then this means that the new force will be 4
times greater, ie 8N * 4 = 32N of gravitational force. </span>