Answer:
The speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.
Explanation:
Given that,
Mass if Jocko, m = 60 kg
Mass of the ball, m' = 20 kg
Speed of the ball, v = 3 m/s
Let V is the speed of Jocko and the ball move after he catches the ball. The momentum of the system remains conserved. Using the conservation of momentum as :

So, the speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.
As we know that

here we know that


now from above equation we have


so image will form on left side of lens at a distance of 15 cm
This image will be magnified and virtual image
Ray diagram is attached below here
Ceres: Yes!
Namaka: No!
Eris: Yes!
Charon: No. (it's a satellite, and dwarf planet's can't be satellites!)
Haumea: Yes!
Makemake: Yes!
Pluto: Yes!
Glad To Help;)
To solve this problem we will apply the concepts related to gravity according to the Newtonian definitions. From finding this value we will use the linear motion kinematic equations to find the time. Our values are
Comet mass 
Radius 
Rock was dropped from a height 'h' from surface = 1m
The relation for acceleration due to gravity of a body of mass 'm' with radius 'r' is

Where G means gravitational universal constant and M the mass of the planet


Now calculate the value of the time




The time taken for the rock to reach the surface is t = 87.58s
Answer:

(Downwards)
(Towards Left)
Explanation:
As we know that beam is in equilibrium
So here we can use torque balance as well as force balance for the beam
Now by torque balance equation at the pivot we can say

As we know that
mg = 1.40 kN
F = 5 kN
so we will have


Now force balance in vertical direction


(Downwards)
Force balance in horizontal direction


(Towards Left)