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hodyreva [135]
2 years ago
7

Island A is 150 miles from island B. A ship captain travels 240 miles from island A and then finds that he is off course and 200

miles from island B. What bearing should he turn to, so he is heading straight towards island B?
Mathematics
1 answer:
Stells [14]2 years ago
4 0
We know that
Applying the law of cosines: 

<span>c</span>²<span> = a</span>²<span> + b</span>²<span> - 2abcos(C) </span>
<span>where: </span>
<span>a,b and c are sides of the triangle and C is the angle opposite side c </span>

<span>that is </span>
<span>150</span>²<span> = 240</span>²<span> + 200</span>²<span> - 2(240)(200)cos(C) </span>

<span>solve for C </span>

<span>22,500 = 57,600 + 40,000 - 96,000cos(C) </span>
<span>22,500-57,600-40,000 = -96,000cos(C) 
</span>-75,100=-96,000cos (C)
cos (C)=0.7822916
C=arc cos(0.7822916)--------> C=38.53°°

<span>hence, </span>
<span>he should turn in the direction of island b by
180 - 38.53 </span><span>= 141.47 degrees</span>
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Answer:

The equivalent expression

Step-by-step explanation:

Assuming your expression is \log_{15}2^3, then we can use the power property of logarithm , which is \log_ab^n=n\log_ab.

If we let a=15, b=2, and n=3

Then using the power property of logarithm will give us:

\log_{15}2^3=3\log_{15}2

Using the power property of logarithm, the equivalent expression is 3\log_{15}2

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2 years ago
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Point C(3.6, -0.4) divides AB in the ratio 3:2. If the coordinates of A are (-6, 5), the coordinates of point B are ___. If poin
kari74 [83]
When a point divides a line segment into ratios of k1:k2, the formula to find the coordiates of the point is:
x=(k2*x1+k1*x2)/(k1+k2), y=(k2*y1+k1*y2)/(k1+k2), 
(x1,y1) being the coordinates of the starting point, and (x2,y2) coordinates of the end point. 
in this case, 3.6=[2*(-6)+3x2]/5
-12+3x2=18
3x2=30
x2=10

use the same method to find y2: -0.4=(2*5+3y2)/5
3y2=-12
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so the the coordinates of B is (10,-4)

use the same method to find the coordinates of D.

the answer I've got for D is (58/9, -2) please double check my calculation.
4 0
2 years ago
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Zara is serving a fresh pie.she starts by cutting the pie in half and then cuts each half into 4 equal pieces what fraction of t
gladu [14]

Answer:

\boxed{\frac{1}{8}}

Step-by-step explanation:

You are starting with ½ pie. Then you cut it into four pieces.

You want to evaluate ½ ÷ 4

Step 1. Treat the integer as a fraction

\frac{1}{2}\div{\frac{4}{1}}

Step 2. Invert the divisor and change divide to multiply

\frac{1}{2}\times{\frac{1}{4}}

Step 3. Multiply numerators and denominators

\frac{1}{2}\times{\frac{1}{4}} = \mathbf{\frac{1}{8}}\\\\\text{Each piece is } \boxed{\mathbf{\frac{1}{8}}} \text{ of a whole pie.}

5 0
2 years ago
A pet store owner, Byron, needs to determine how much food he needs to feed the animals. Byron knows that he needs to order the
Brums [2.3K]

Answer:

He needs to buy 120 packages of dod food.

Step-by-step explanation:

b - bird food

h - hamster food

d - dog food

c - cat food

b + h + d + c = 600

b = h (bird food is the <em>same</em> as hamster food)

b = 4 d (bird food is <em>4 times</em> dod food)

c = d/2 (cat food is <em>half</em> dog food)

Total of packages ordered.

b + b + d + c = 600

4d + 4d + d + d/2 = 600

4 d + 4 d + d + d = 600. 2

10 d = 1.200

d= 120 .........the amount of dog food packages.

     

6 0
2 years ago
The number of bacteria in a petri dish on the first day was 113 cells. If the number of bacteria increase at a rate of 82% per d
Tresset [83]

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

3 0
2 years ago
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