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Snezhnost [94]
2 years ago
5

A carnival game allows a group of players to each draw and keep a marble from a bag. The bag contains 5 gold marbles, 25 silver

marbles, and 70 red marbles. A player wins a large prize for drawing a gold marble and a small prize for drawing a silver marble. There is no prize for drawing a red marble. At the start of the game, the probability of winning a large prize is 0.05 and the probability of winning a small prize is 0.25. Suppose that the first player draws a silver marble and wins a small prize. What is the probability that the second player will also win a small prize? If a group of four plays the game one at a time and everyone wins a small prize, which player had the greatest probability of winning a large prize? How could the game be made fair for each player? That is, how could you change the game so that each player has an equal chance of winning a prize?
Mathematics
1 answer:
laila [671]2 years ago
3 0
1. What’s the probablity of a second person winning the small prize?
There are now 99 total marbles, and 24 silver marbles. So, 24/99 is 0.24 probability.
2. Which player is most likely to win a big prize?
Since each player draws a silver marble (aka a small prize) there are less small prize marbles in the bag after each turn. So, the first person would have a 5% chance (or 0.05)of winning the big prize gold marble, but the last person would have a slightly bigger chance (5.15% or 0.0515) of winning a big prize.
3. How could the game be made fair for each player?
Well it’s quite simple, just have each player return their marble and the number of marbles would be kept constant, giving everyone an equal chance. Or you could have them all play at the same time, either way.
4. Same answer as 3
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<u>Answer</u>

3×(2×5)

<u>Explanation</u>

Multiplication of numbers is associative. For example,

(a×b)×c = a×(b×c)

This is also called grouping. We multiply more than 2 numbers by grouping.

For the equation given above, (3x2)x5, it can also be grouped as 3×(2×5).

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When you select a random person, the probability that this person will go to Ches
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Answer: a= 0.0231

Step-by-step explanation:

n=8

p=0.75

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(p=x)

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What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4
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5k - 2k = 12
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I hope that helps!
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HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

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2 years ago
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