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Korolek [52]
2 years ago
8

The graph of f(x) = 2x is shown on the grid. The graph of g(x) = ()x is the graph of f(x) = 2x reflected over the y-axis. Which

graph represents g(x)?
Mathematics
2 answers:
dlinn [17]2 years ago
9 0

The graph would be g(x) = -2x

When we reflect linear graphs over the y-axis, the y-intercept stays exactly the same. The slope then reverts to a negative form of its original. So we turn the 2 to -2 and keep the 0 for y-intercept.

This gives us g(x) = -2x

lakkis [162]2 years ago
7 0

Answer:

While the graph is not shown, it would be the graph of g(x) = -2x.

Step-by-step explanation:

A reflection across the y-axis negates the x-coordinate of every point.  To find the function associated with this, we would replace x with -x:

g(x) = f(-x) = 2(-x) = -2x

The function would be g(x) = -2x.

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Lois bought clothing at a store. She did not have enough in her bank account to pay for the purchase. After receiving the bill a
fomenos
<span>Lois used a credit card to make the purchase. 

One can't purchase an item that costs more than the balance in a debit card. The debit card is equivalent to cash on hand. You can only spend what you have. 

The credit card is equivalent to a loan. You don't have the money as of the moment but when you use the credit card, you owe the issuing bank the amount you've put on credit. The bank will pay the merchant and you will pay the bank. Interest is an additional expense when you pay your bill beyond the due date. The interest is applied on the amount outstanding upon the payment due date. </span>
8 0
2 years ago
Read 2 more answers
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
A frog catches insects for his lunch. The frog likes to eat flies and mosquitoes in a certain ratio, which is shown in the diagr
avanturin [10]

Answer:

ON MONDAY:  35 mosquitos.

ON TUESDAY: 6 flies.

Step-by-step explanation:

As you can see in the diagram, the frog eats 3 flies for every 7 mosquitoes (for lunch). Then you can expresed this ratio as following:

3:7 or \frac{3}{7}

Based on the table:

-If the frog eats 15 flies on monday, then the number of mosquitos that it eats can be calculated as following:

\frac{3}{7}=\frac{15}{mosquitoes}\\\\mosquitoes=\frac{15*7}{3}\\\\mosquitoes=35

-If the frog eats 14 mosquitoes on tuesday, then the number of flies that it eats can be calculated as following:

\frac{3}{7}=\frac{flies}{14}\\\\flies=\frac{14*3}{7}\\\\flies=6

8 0
2 years ago
The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave
kkurt [141]

Answer:

<u>0.9524</u>

Step-by-step explanation:

<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>

<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>

<em />

<u>Solution:</u>

This is conditional probability.

Given:

  • Probability train arrive on time and leave on time = 0.8
  • Probability train arrive on time = 0.84
  • Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

P(Leave \ on \  time | arrive \  on \ time) = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = <u>0.9524</u>

<u></u>

<u>This is the answer.</u>

5 0
2 years ago
The class president collected data on 150 randomly selected 17-year-olds at his school. He surveyed students on if they had a jo
telo118 [61]

Answer:

Step-by-step explanation:

Part A can be seen in the attached picture below. Since there are 76 students that have both a license and a job we need to subtract 76 from each to get the amount that only have either a license or a job as seen in the table. Also we can see from the table that it sums up to 145 students, meaning that 5 students do not have neither a job or a license.

Part B, to calculate this we need to divide the amount of students that ONLY have a job by the total amount of students that have a job (since the rest of those students also have a license) Therefore:

17 / 93 = 0.1828

Now we can multiply this result by 100 to get the percentage.

0.1828 * 100 = 18.28%

8 0
2 years ago
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