Which state of matter has the least energetic molecules?

Complete the following sentence: The cathode in a voltaic cell is the electrode _____________.

Sergio [31]

Answer:

to which cations from the salt bridge migrate

Explanation:

A voltaic cell is an electrochemical cell that uses spontaneous redox reactions to generate electricity. It's composed of a cathode, an anode, and a salt bridge.

In cathode, the substance is gaining electrons, so it's reducing, in the anode, the substance is losing electrons, so it's oxidating. The flow of electrons is from the anode to the cathode.

The salt bridge is a bond between the cathode and the anode. When the redox reaction takes place, the substances produce its ions, so the solution is no more neutral. The salt bridge allows the solutions to become neutral and the redox reaction continues.

So, the cathode produces anions, which goes to the anode, and the anode produces cations, which goes to the cathode. Then, the cathode n a voltaic cell is the electrode to which cations from salt bridge migrate and where the reduction takes place.

7 0

2 years ago

Write a complete step-by-step plan for dealing with broken glassware on the floor or lab table. Write your plan in list form in

zzz [600]

1 tell the person in charge or the teacher
2 make sure u did not get cut
3 get the large pieces and put them into glass waist container
4 get broom or brush weep area and get small pieces depose in same place
5 take a wet wipe and cover area to pick up anything that as missed!

3 0

2 years ago

Read 2 more answers

A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of

Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0

2 years ago

Interpret the following Arterial Blood Gases 1. pH 7.33 PaCO2 60 HCO3 34 A. Normal ABG values B. Respiratory acidosis without co

kicyunya [14]

Answer: 1) C; 2)D; 3)B; 4)B; 5) A

Explanation:Interpreting the following Arterial Blood gases, we have

1. pH 7.33 PaCO2 60 HCO3 34----Respiratory acidosis with partial compensation----C

2. pH 7.48 PaCO2 42 HCO3 30------. Metabolic alkalosis without compensation----D

3. pH 7.38 PaCO2 38 HCO3 24 ----- Normal---B

4. pH 7.21 PaCO2 60 HCO3 24------ Respiratory acidosis without compensation-----B

5. pH 7.48 PaCO2 28 HCO3 20 ----Respiratory alkalosis with partial compensation

The Arterial blood gas interpretation from analysis shows the pH and the partial pressures of oxygen and carbon dioxide in the arterial blood of an individual which can detect how well the lungs are functioning thereby making a physician make a diagnosis, estimate the severity of a condition and profer treatment.

4 0

2 years ago

A. The measured pH of a 0.100 M HCl solution at 25 degrees Celsius is 1.092. From this information, calculate the activity coeff

ra1l [238]

Answer:

activity coefficient $\mathbf{\gamma =0.809}$