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Inga [223]
2 years ago
10

One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What

weight of candies did they each eat?
Mathematics
2 answers:
VARVARA [1.3K]2 years ago
8 0

Let us say there are x number of candies .

For first student,

He ate 3/20 of all candies, so 3/20 (x)

He also ate 1.2 lb of candies.

Total candies first student ate = (3/20) x +1.2

Second student ate 3/5 of all candies that is (3/5)x

He also ate 0.3 lb of candies.

Total candies second student ate = (3/5)x +0.3

Since total candies for both will be same, so equating the two expressions

\frac{3}{20} (x) +1.2 = \frac{3}{5} x +0.3

x=2

So there are 2 lb of candies in total.

First student ate = 0.3 +1.2 = 1.5lb of candies.

Second student ate = 1.5 lb of candies

olga nikolaevna [1]2 years ago
8 0

Answer:

2 pounds of candy:)

Step-by-step explanation:

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Answer:

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when a sample is selected in a manner that some elements, in this case patients, of population have higher or lower probability of sampling then that sample is biased.

From given case, all the following are biased samples

all her patients patients with no cavities

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4 0
2 years ago
Matthew manages the packaging department of his company. Yesterday, the department operated for only 4 hours due to a company pi
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Alright, lets get started.

If Matthew wants to complete packages at an average rate of at least 39 packages per hour.

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Suppose they are working today t hrs, and his department will complete 43 packages per hour today.

It means they are going to make 43 t packages today.

This 43 t packages includes those 44 too , which they are short of yesterday due to picnic.

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Cross multiplying

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Adding 44 in both sides

39 t + 44 = 43 t - 44 + 44

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Subtracting 39 t in both sides

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Hence they have to woth 11 hrs today : Answer

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