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Inga [223]
2 years ago
10

One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What

weight of candies did they each eat?
Mathematics
2 answers:
VARVARA [1.3K]2 years ago
8 0

Let us say there are x number of candies .

For first student,

He ate 3/20 of all candies, so 3/20 (x)

He also ate 1.2 lb of candies.

Total candies first student ate = (3/20) x +1.2

Second student ate 3/5 of all candies that is (3/5)x

He also ate 0.3 lb of candies.

Total candies second student ate = (3/5)x +0.3

Since total candies for both will be same, so equating the two expressions

\frac{3}{20} (x) +1.2 = \frac{3}{5} x +0.3

x=2

So there are 2 lb of candies in total.

First student ate = 0.3 +1.2 = 1.5lb of candies.

Second student ate = 1.5 lb of candies

olga nikolaevna [1]2 years ago
8 0

Answer:

2 pounds of candy:)

Step-by-step explanation:

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Answer:

a.  5 + 2i, 13 + 2i, 29 + 2i

Step-by-step explanation:

We'll use the formula  f(z) = 2z + (3 - 2i)  for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with z0 = 1 + 2i and we plug that into the base equation:

z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i

z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i

z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i  + 3 - 2i = 29 + 2i

z3 = 29 + 2i

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2 years ago
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<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

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10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

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11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

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2 years ago
If the product of two consecutive integers is decreased by 20 times the greater integer, the result is 442. find the integers
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Translating the word problem into symbols, x(x+1)-20(x+1) = 442.

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or      x^2 - 19x - 462 = 0

Solve by completing the square:

          x^2 - 19x + 90.25 - 90.25 - 462 = 0

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Taking the positive square root of both sides, we get x-9.5 = 23.5, or
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The two consecutive integers are 33 and 34.

Check:  (33)(34)-20(34) = 442 (as expected).

            
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