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Natali [406]
2 years ago
13

A scientist hypothesizes that fertilizer containing 10 percent nitrogen will produce tomato plants with more leaves and blossoms

than fertilizer containing 15 percent nitrogen. What is the independent variable?
Chemistry
2 answers:
nlexa [21]2 years ago
3 0
The number of leaves and blossoms
OleMash [197]2 years ago
3 0

Answer:

In the given case, the independent variable will be the amount of nitrogen present in the fertilizer.

Explanation:

In an experiment, an independent variable refers to the variable, which is controlled or changed, it is the variable that is used by the researcher to examine their dependent variable. In the given case, the amount of nitrogen present in the fertilizer will be the independent variable, as it is not reliant upon any other kind of variable.  

Also, from being not dependent on other variables, it is a variable on which other variables relies upon, and in the given case, it will be the number of blossoms and the number of leaves grown on the tomato plant with the application of the fertilizer.  

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Scott traveled 10 miles in his journey.

<u>Explanation</u>:

Scott first travels 5 miles in north direction, then he turns to west and covers 3 miles distance finally he turns to south and travels 2 miles. We need to find the total distance covered by the Scott. To find the distance we should sum up all the distances he covered in three directions 5 miles north + 3 miles west + 2 miles south = 10 miles.

Therefore we can conclude that the total distance traveled by the Scott is 10 miles.  

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2 years ago
According to the kinetic theory, collisions between molecules in a gas _____.
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2 years ago
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

[Ca2+]= 0.050 M   [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

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