Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)
F = 900 ÷_________
Answer: Got It!
<em>Explanation:</em> Guide A Starts From Rest With Pin P At The Lowest Point In The Circular Slot, And Accelerates Upward At A Constant Rate Until It Reaches A Speed Of 175 Mm/s At The ... In the design of a timing mechanism, the motion of pin P in the fixed circular slot is controlled by the guide A, which is being elevated by its lead screw.
Answer:
a) xf = 5.1 m
b) u = 0.304
c) x = 10.3 m
Explanation:
we will use the following formula:
u = 0.1 + A*x
Si x = 12.5 m, u = 0.6
Clearing A:
A = 0.5/12.5 = 0.04 m^-1
a) we have to:
W = Ekf - Eki
where Ekf = final kinetic energy
Eki = initial kinetic energy
9.8*(0.1xf + ((0.04*xf^2)/(2))) = (4.5^2)/(2)
Clearing xf, we have:
xf = 5.1 m
b) Replacing values for u:
u = 0.1 + (0.04*5.1) = 0.304
c) Wf = Ekf - Eki
-u*m*x*g = 0 - (m*v^2)/2
Clearing x:
x = v^2/(2*u*g) = (4.5^2)/(2*0.1*9.8) = 10.3 m
To solve this problem we will apply the concepts related to energy conservation. Here we will use the conservation between the potential gravitational energy and the kinetic energy to determine the velocity of this escape. The gravitational potential energy can be expressed as,

The kinetic energy can be written as,

Where,
Gravitational Universal Constant
Mass of Earth
Height
Radius of Earth
From the conservation of energy:

Rearranging to find the velocity,
Escape velocity at a certain height from the earth
If the height of the satellite from the earth is h, then the total distance would be the radius of the earth and the eight,


Replacing the values we have that


Therefore the escape velocity is 3.6km/s
Answer:
The temperature of the gas is 1197.02 K
Explanation:
From ideal gas law;
PV = nRT
Where;
P is the pressure of the gas
V is the volume of the gas
R is ideal gas constant = 8.314 L.kPa/mol.K
T is the temperature of the gas
n is the number of moles of gas
Volume of the gas in the cylindrical container = πr²h
Given;
r = 6/2 = 3 cm = 0.03 m
h = 11 cm = 0.11 m
V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L
number of moles of oxygen gas = Reacting mass / molar mass


Therefore, the temperature of the gas is 1197.02 K