Perimeter (P)= 2Length (L) +2Width (W)
P=2L + 2W
P=(2y)+(3y-5)
P=5y-5
A. 5y-5
I believe that this problem has the following choices:
It must be equal to BQ .<span>
It must be wider than when he constructed the arc centered at
point A.
It must be equal to AB .
It must be the same as when he constructed the arc centered
at point A.</span>
The correct answer is the last one:
It must be the same as when he constructed the arc centered
at point A.
<span> </span>
There are 12 different ways to organize your schedule
There are 2 English classes
There are 3 math classes
There are 3 history classes
Take 2x3x3 and you get 12
Assuming that the 1.5% annual interest is split into monthly basis with the same amount, then the monthly interest should be: 1.5%/12= 0.125%.
If you put $1000 for annual interest, the saving account would become: $1000*(100%+1.5%)= $1015
If you put $1000 for monthly interest, the saving account would become: ($1000*(100%+0.125%)= $1000*1.0151035559= $1015.10
Then, the money difference should be: $1015.10-$1015= $0.10
The easiest way, I think, is to convert the mixed number into an improper fraction, then multiply by 3.
3 1/2 = 7/2
7/2 · 3 = 21/2
now just change the improper fraction back to a mixed number by dividing and putting the remainder into fraction form
21/2 = 10 1/2
You could also multiply the whole number by 3 and the fraction by 3, ending up with 9 3/2, but then have to convert the improper fraction into a mixed number
3/2 = 1 1/2
then add the numbers together
9 + 1 1/2 = 10 1/2
either way works, whatever is easiest for you.