Question

acetone a common solvent has a density of 0.79 g/cm3 at 20. what is the volume of 85.1 g of acetone at 20 c? what is the mass of 125 mL of acetone at 20 c?

Answer 1

Answer: 1. The volume of acetone is $108cm^3$

2. The mass of acetone is 99 g.

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of acetone = 85.1 grams

Density of acetone = $0.79g/cm^3$

Putting in the values we get:

$0.79g/cm^3=\frac{85.1g}{Volume}$

$Volume=108cm^3$

Thus the volume of acetone is $108cm^3$

2. $Density=\frac{mass}{Volume}$

Given : Mass of acetone = ?

Density of acetone = $0.79g/cm^3=0.79g/ml$     $1cm^3=1ml$

Volume of acetone = $125cm^3=125ml$  

Putting in the values we get:

$0.79g/ml=\frac{mass}{125ml}$

$mass=99g$

Thus mass of acetone will be 99 g.

Answer 2

the volume of acetone = V= 107.72 cm³

the mass of acetone = m = 98.75 gr

Further explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density

The unit of density can be expressed in g/cm³ or kg/m³

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr/cm³

Acetone has a density of 0.79 g/cm³ at 20° C

• the volume of 85.1 g of acetone at 20° C :

$\boxed{\bold{V=\frac{85.1\:gr}{0.79\:\frac{gr}{cm^3} }}}$

V= 107.72 cm³

• the mass of 125 mL of acetone at 20° C

$\boxed{\bold{m=0.79\:\frac{gr}{cm^3}\times 125\:cm^3}}}$

m = 98.75 gr

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Keywords: density, mass, volume, acetone, solvent