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Marrrta [24]
2 years ago
5

A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa

nce in the periodic table?
A. Right or middle of the table because it is a non-metal.
B. Left or middle of the table because it is a non-metal.
C. Left or middle of the table because it is a metal.
D. Right or middle of the table because it is a metal.
Chemistry
2 answers:
Aleks04 [339]2 years ago
5 0
The answer is D only metals are shiny and highly malleable
sergejj [24]2 years ago
5 0

Answer: Option (D) is the correct answer.

Explanation:

Metals are the substances which donate electrons to complete their octet. They are malleable and ductile in nature. They are able to conduct heat and electricity. Metals have shiny surface and sonorous in nature.

Metals are placed at the left and middle of periodic table.

Whereas non-metals are the substances which accept electrons to complete their octet. They are poor conductors of heat and electricity. They are brittle and non-sonorous in nature.

Non-metals are placed at the right of periodic table.

Hence, we can conclude that right or middle of the table because it is a metal best explains the probable position of the substance in the periodic table.

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A column is filled with four different liquids of different densities. A red liquid, a blue liquid, a green liquid, and a purple
Svet_ta [14]

<em>Answer:</em>

The order of liquid from top to bottom is as follow

  •        Purple, green, red, blue

<em>Explanation:</em>

Chart of densities:

  •   Red = 1.2 g/cm∧3
  •   Blue = 1.6 g/cm∧3
  •   green = 0.8 g/cm∧3
  •   Purple = 0.1 g/cm∧3

<em>Density:   </em>

Density is the ratio of mass and volume as follow

                             d = m/v

<em>Summary:</em>

  • Greater the density, it will be at bottom and vice versa.
  • Blue liquid has greater density so it will be at bottom
  • Purple liquid has low density, so it will be at top.
5 0
2 years ago
Read 2 more answers
A 600.0 mL sample of 0.20 MHF is titrated with 0.10 MNaOH. Determine the pH of the solution after the addition of 600.0 mL of Na
Leona [35]

Answer: pH=12.69

Explanation:

{\text{Moles of HF}=Molarity\times {\text{Volume of solution in liters}}

{\text{Moles of HF}=0.20M\times 0.6L=0.12 moles

HF\rightarrow H^++F^-

Initial 0.12               0       0

Eqm   0.12-x           x        x

K_a=\frac{[H^+][F^-]}{[HF]}

3.5\times 10^{-4}=\frac{x^2}{0.12-x}  

(neglecting small value of x in comparison to 0.12)

x=4.2\times 10^{-5}

Moles of H^+=4.2\times 10^{-5}

NaOH\rightarrow Na^++OH^-

{\text{Molesof NaOH}}=Molarity\times {\text{Volume of solution in liters}}

{\text{Moles of NaOH}}=0.10M\times 0.6L=0.06 moles

0.06 moles of NaOH will give 0.06 moles of [OH^-]

Now 4.2\times 10^{-5} moles of OH^- will be neutralized by 4.2\times 10^{-5} moles of H^+ and (0.06-4.2\times 10^{-5})=0.059 moles of OH^- will be left.

Molarity of OH^-=\frac{0.059moles}{1.2L}=0.049M

pOH=-\log[OH^-]=-\log[0.049]=1.31

pH = 14 - pOH= 14 - 1.31 = 12.69

5 0
2 years ago
What is the concentration of a solution made with 0.150 moles of KOH in 400.0 mL of solution?
otez555 [7]

Answer:

concentration = \frac{0.15}{0.4}=0.375 mol/L

Explanation:

Concentration: i is defined as the mole per litre.

concentration = \frac{mole}{volume in L}

mole=0.15

volume=400 ml=0.4 litre

concentration = \frac{0.15}{0.4}=0.375 mol/L

6 0
2 years ago
What atomic or hybrid orbitals make up the bond between c2 and o in acetaldehyde, ch3cho?
SSSSS [86.1K]

Acetaldehyde is an organic compound (a compound containing C atoms) composed of a carbonyl group. On the other hand, a carbonyl group is a functional group containing C = O. The hybrid orbitals of a compound determines the number pi and s orbitals in the electronic configuration. For a single bond, there are two s orbitals. For double bonds, on the other hand, the number of s orbital bond is 1 while the number of pi bonds is 2. For triple bonds, there are three pi bonds present in the cloud.

Thus for a c = O bond, the atomic orbital configuration is sp3 containing 1 s orbital and 2 pi bonds. 

8 0
2 years ago
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Answer:

Drug calculation

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Then what mass in g of clobetasol is in 0.03%w/w = 45 x 0.03/0.05 =27g

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3 0
2 years ago
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