Two distinct roots means two real solutions for x (the parabola needs to cross the x-axis twice)
Vertex form of a quadratic equation: (h,k) is vertex
y = a(x-h)^2 + k
The x of the vertex needs to equal 3
y = a(x-3)^2 + k
In order to have two distinct roots the parabola must be (+a) upward facing with vertex below the x-axis or (-a) downward facing with vertex above the x-axis. Parabolas are symmetrical so for an easy factorable equation make "a" 1 or -1 depending on if you want the upward/downward facing one.
y = (x-3)^2 - 1
Vertex (3,-1) upwards facing with two distinct roots 4 and 2
y = x^2 -6x + 9 - 1
y = x^2 -6x + 8
y = (x - 4)(x - 2)
Step-by-step explanation:
Points are (8,5) and (-12,-9)
The equation of a line passing through two points is given by :
or
But he writes the equation 7x – 10y = 3 which is not matching with the one we have calculated. It means that model calculated by Devon is not good.
Answer:
No
Step-by-step explanation:
Because, the Pythagorean Inequality Theorem states that the two smallest angles should add up to be more than the third angle.
4+6=10
11 is bigger than 10, still.
Therefore, no the triangle is not possible.
The given function is
f(x) = log₁₀(5x-1)
As x -> -∞, the argument of the log function becomes a large negative number.
Because the log of a negative number is undefined, f(x) is undefined as x -> -∞.
As x -> +∞, the argument of the log function becomes a large positive number.
Therefore f(x) -> +∞ as x -> +∞.
Answer:
As x -> -∞, f(x) is undefined.
As x-> +∞, f(x) -> +∞.
