Enter the expression 14/7N+α, where α is the lowercase Greek letter alpha. Express your answer as a chemical expression.
2 answers:
Core reactions that occur:
¹⁴₇N + ⁴₂He → ¹⁷₈O + ¹₁H
<h3>Further explanation</h3>Fusion and fission reactions are reactions involving atomic nucleus reactions
Fission reaction is a nucleation division reaction by firing a particle usually neutron so that it gets smaller particles of atomic nuclei.
Example:
Uranium nuclei division reaction
²³⁵₉₂U + ¹₀n -> ⁸⁹₃₆Kr + ¹⁴⁴₅₆Ba + 3¹₀n
In this reaction, Uranium splits into Kr and Ba isotopes and releases energy and gamma radiation
Energy is generated based on the isotope mass from the beginning of the reaction and after division
A fusion reaction is a combining reaction of 2 atomic nuclei. Usually what is often used is a reaction between the hydrogen isotope that will form Helium
³₁Ti + ²₁D -> ⁴₂He + ¹₀n
Isotopes of Hydrogen Tritium and Deuterium form Helium
At the core, reaction applies the law of eternity
- 1. energy
the energy before and after the reaction is the same
- 2. atomic number
the number of atomic numbers before and after the same
- 3. mass number
the number of mass numbers before and after the same
Particles that play a role in core reactions include
alpha α particles ₂He⁴
beta β ₋₁e⁰ particles
gamma particles γ
positron particles ₁e⁰
In general, the core reaction equation can be written:
X = target core
a = particle fired
Y = new core
b = the particle produced
Q = heat energy
or can be written simply
X (a, b) Y
In the ¹⁴₇N atomic nucleus, it is shot with alpha ⁴₂He rays which produce isotopes of Oxygen and ¹₁H protons.
¹⁴₇N + ⁴₂He → ¹⁷₈O + ¹₁H
This reaction can be written down
¹⁴₇N (α, H) ¹⁷₈O
The sum of the atomic numbers and mass numbers before and after are the same
<h3>Learn more</h3>
nuclear decay reaction
Plutonium − 239
exponential decay
Keywords: Fusion and fission reactions, alpha ₂He⁴, nuclei
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Answer: a)
b)
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
a) Mass of Ba= 66.06 g
Mass of Cl = 34.0 g
Step 1 : convert given masses into moles.
Moles of Ba =
Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Ba =
For O =
The ratio of Ba: Cl= 1:2
Hence the empirical formula is
b) Mass of Bi= 80.38 g
Mass of O= 18.46 g
Mass of H = 1.16 g
Step 1 : convert given masses into moles.
Moles of Bi =
Moles of O=
Moles of H=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Bi=
For O =
For H=
The ratio of Bi: O: H= 1:3: 3
Hence the empirical formula is