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2 years ago

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The total cost after tax to repair Deborah’s computer is represented by , where h represents the number of hours it takes to rep

air Deborah’s computer. What part of the expression represents the amount of tax Deborah has to pay? Explain how you know you are correct.

1 answer:

Vlada [557]2 years ago

6 0

0.08 (50h) Is The Tax. The reason I am correct would be: because 0.08 = 8%, and 0.08 * 50h Gives You 8% Of 50h.

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In a group of 120 students,68 had riddena bus,78 had ridden the LRT,20 had riddenthe bus and the jeep ,19 had ridden the LRT and

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Answer:

575786

Step-by-step explanation:

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Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal pla

svp [43]

Here is the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29: 117 122 129 118 131 123

Men aged 60-69: 130 153 141 125 164 139

Group of answer choices

a)

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

$coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{117+122+129+118+131+123}{6}$

Mean = $\dfrac{740}{6}$

Mean = 123.33

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{161.3334}{5}}$

Standard deviation = $\sqrt{32.2667}$

Standard deviation = 5.68

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{5.68}{123.33}*100$

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{ 130 + 153 + 141 + 125 + 164 + 139}{6}$

Mean = $\dfrac{852}{6}$

Mean = 142

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{1048}{5}}$

Standard deviation = $\sqrt{209.6}$

Standard deviation = 14.48

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{14.48}{142}*100$

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

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2 years ago

Which of the following options is an equivalent function to f(x) = 4(3)2X?

Paha777 [63]

Answer:

$f(x)=4(6x)$

Step-by-step explanation:

Given:

the given expression is.

$f(x)=4(3)2x$

Simplify the given expression.

$f(x)=4(3)2x$

$f(x)=4(3\times 2x)$

$f(x)=4(6x)$

Therefore, the option $f(x)=4(6x)$ is an equivalent function to $f(x)=4(3)2x$ .

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Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0. S

mixas84 [53]

Answer:What was done from the first to the second equation was that the fraction was simplified. 126 and 32 have a common factors of 2.

126/32=(63*2)/(16*2)

The 2s in the top and bottom can cancel out, leaving the fraction 63/16.

In addition, since there are x terms on the top and bottom, they cancelled out as well.

x/x^3=1/x^2

This leaves an x^2 term on the bottom.

Thus, if a is 16, and b is 2, you will have an equivalent form of the fraction.

Step-by-step explanation:

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The measure of central angle QRS is StartFraction 8 pi Over 9 EndFraction radians. What is the area of the shaded sector? 36Pi u

MArishka [77]

The question is missing the figure. So, it is attached below.

Answer:

Area of the shaded sector is <u>144π units squared</u>.

Step-by-step explanation:

Given:

Central angle of the sector is, $\theta=\frac{8\pi}{9}\ rad$

Radius of the circle is, $R=18\ units$

We know that, area of a sector of a circle of radius 'R' and central angle $\theta$ is given as:

$A=\frac{1}{2}R^2\theta$

Plug in $\theta=\frac{8\pi}{9},R=18$ . This gives,

$A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2$

Therefore, the area of the shaded sector is 144π units squared.

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2 years ago

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