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PilotLPTM [1.2K]
2 years ago
10

Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of

50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be joules. The braking distance at the faster speed is the braking distance at the slower speed.
Physics
2 answers:
Mariana [72]2 years ago
7 0

ke prop to v^2

ke1/v1^2=ke2/v2^2

400/50x50=joules/100x100

400x2x2

1600j

melisa1 [442]2 years ago
3 0

Answer:A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be 1,600  joules. The braking distance at the faster speed is double the braking distance at the slower speed.

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
rosijanka [135]

Answer:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

Explanation:

For this case we know that the initial velocity is given by:

v_i = 7 \frac{m}{s}

The final velocity on this case is given by:

v_f = 13 \frac{m}{s}

And we know that it takes 8 seconds to go from 7m/s to 13m/s. We can use the following kinematic formula in order to find the acceleration during the first interval:

v_f = v_i +at

If we solve for the acceleration we got:

a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}

So for the other traject we assume that the acceleration is constant and the train travels for 16 s. The initial velocity on this case would be 13m/s from the first interval and we can find the final velocity with the following formula:

v_f = v_ i +a t

And if we replace we got:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

5 0
2 years ago
A car wheel turns through 277° in 10.7 s. Calculate the angular speed of the wheel.
slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

Explanation:

The angle through which the car wheel turns, Δθ = 277° = 277/360 × 2·π radian

The time it takes for the car wheel to turn, Δt = 10.7 s

The angular speed, ω is given by the following equation;

Angular \ speed = \dfrac{Change \ in \ angular \ rotation }{Change \ in \ time} = \dfrac{\Delta \theta}{\Delta t}

Substituting the known values for Δθ and Δt gives;

Angular \ speed = \dfrac{\dfrac{277 ^{\circ}}{360 ^{\circ }  }  \times 2 \times \pi \ radian}{10.7 \ seconds} \approx 0.452 \ rad/s

The angular speed of the wheel = 0.452 rad/s

3 0
2 years ago
A 45-mH inductor is connected to an ac source of emf with a frequency of 250 Hz and a maximum emf of 20 V. If the voltage across
ruslelena [56]

Answer:

-20v

Explanation:

Data provided in the question as per the given situation

L = 45 mH

f = 250 Hz

V_o = 20V

Based on the above information, let us assume voltage across inductor be V at t

So,

V = 20 sin (2 \pi \times 250\times t + \frac{\pi}{2})

t = 2 ms

Now

The voltage at time t = 2.0 ms is

V_1 = 20 sin (500\times 2\times 10^{-1} \times \pi + \frac{\pi}{2})

= 20 sin(\pi + \frac{\pi}{2} )

= -20 volt

= -20v

We simply solved the above equation so that the correct voltage could come

5 0
2 years ago
Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is yo
nalin [4]

Answer:

Ok, let's suppose the simplest of the physical changes:

We have an object that is not moving (so it is not accelerated)

and there is change, now the object moves.

Because there was a change, means that there was an acceleration, and by the second Newton's law.

Force equals mass times acceleration:

F = m*a

There must be a force.

So suppose that you pushed the object, then some energy that you had, you transferred it to the object, that now is moving and now has kinetic energy.

Now, is kinda true that in a closed system the total energy is always constant, but it depends on what is our system.

So if we think in our system as you and the object, then in the whole system the energy does not change because the energy that you lost is now on the object, but again, there was a transfer of energy.

So no, your friend is not correct.

3 0
2 years ago
Taylor places a nail on a bar magnet. The nail sticks to the magnet when lifted up off the table. She touches a paperclip to the
Bas_tet [7]

Answer:

When touching the bar magnet ,the nail gets attached to the magnet from its metallic field is used to connect when taylor touched the nail to the bar magnet,the magnetic fields were ranged,and made a temporary magnet.

Explanation:

3 0
2 years ago
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