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Semmy [17]
2 years ago
8

A force f = bx 3 acts in the x direction, where the value of b is 3.7 n/m3. how much work is done by this force in moving an obj

ect from x = 0.00 m to x = 2.7 m?
Physics
1 answer:
Elodia [21]2 years ago
8 0
The answer would be 21.6 but rounded up it would be 22J.
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Nitrogen (n2) gas within a piston–cylinder assembly undergoes a compression from p1 = 20 bar, v1 = 0.5 m3 to a state where v2 =
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Part a)

As we know that

P_1V_1^{1.35} = P_2V_2^{1.35}

here we know that

P1 = 20 bar

V1 = 0.5 m^3

V2 = 2.75 m^3

from above equation

20* 0.5^{1.35} = P * (2.75)^{1.35}

P = 2 bar

so final state pressure will be 2 bar

Part b)

now in order to find the work done

W = \int PdV

W = \int \frac{c}{V^{1.35}}dV

W = c\frac{V^{-0.35}}{-0.35}

W = \frac{P_1V_1 - P_2V_2}{0.35}

W = \frac{20* 0.5 - 2 * 2.75}{0.35}* 10^5 = 12.86 * 10^5 J

3 0
2 years ago
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A 1.0 kg object is attached to a string 0.50 m. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s. A b
aivan3 [116]
<span>50 N The centripetal force upon an object is expressed as F = mv^2/r So let's substitute the known values and calculate F = mv^2/r F = 1.0 kg * (5.0 m/s)^2 / 0.5 m F = 1.0 kg * 25 m^2/s^2 / 0.5 m F = 25 kg*m^2/s^2 / 0.5 m F = 50 kg*m/s^2 F = 50 N So the answer is 50 N which matches one of the available choices.</span>
6 0
2 years ago
A 2400-kg satellite is in a circular orbit around a planet. the satellite travels with a constant speed of 6670 m/s. the radius
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The gravitational force exerted on the satellite is called the centrifugal force, the force keeping it orbiting to the planet. Its formula is F= mass times the square of the velocity all over the radius.Thus,

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I hope I was able to help you. Have a good day.
4 0
2 years ago
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What is the mass and density of 237 mL of water
oee [108]

Answer:

<h2><em>V(water)= 237 mL=237×10^-6 m^3</em></h2><h2><em>ρ(water)=1000 kg/m^3</em></h2><h2><em>m=</em><em>ρ×V=(1000)×(237×10^-6)</em></h2><h2><em>m= 237×10^-3 = 0.237 kg</em></h2><h2><em>m= 237 gram.</em></h2>
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2 years ago
A monoatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.010 m^3 to 0.040 m^3. The fina
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Answer:

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

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