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guapka [62]
2 years ago
6

An unstable nucleus which has a tendency to spontaneously change its form with the emission of high-energy particles or photons

is said to be _____________
Physics
2 answers:
Bezzdna [24]2 years ago
8 0

Answer: Radioactive nucleus.

Explanation: First, we can define the radiation as the emanation of particles or photons, for example, a flashlight is radiating photons when it is turned on.

So a neutron that emanates particles or photons when change form, is a nucleus that radiates, and those are called "radioactive nucleus"

Where radioactive implies that there is a presence of radiation in some way. In this case, the radiation is caused because the nucleus goes from an energetic state to other with lower energy, and that energy must be dissipated in some way, in this case, in form of radiation.

Pepsi [2]2 years ago
6 0

Answer:Radioactive

Explanation:

The radioactive nucleus is the one which does not has enough binding energy to hold the nucleus in a stable state and thus radiates either electron or proton to become a stable element.

A radioactive element is formed when after billions of years such as uranium and thorium. The stability of the nucleus depends upon the opposition of attractive and repulsive force among the nucleus.

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A goat enclosure is in the shape of a right triangle. One leg of the enclosure is built against the side of the barn. The other
san4es73 [151]

Answer:

16,18,22

Or

1,3,7

Explanation:

The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation

8 0
2 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
valentina_108 [34]

Answer:

v = 69.82 ms^-1

Explanation:

As we know,

R = vi2 sin2Ꝋ / g  

vi2 =R g / sin2 Ꝋ where R is range R = 52m, Ꝋ = 3 Degrees

vi2 = 52 x 9.8 / sin 2(3) = 4875.227

v = 69.82 ms^-1

3 0
2 years ago
Two insulated copper wires of similar overall diameter have very different interiors. One wire possesses a solid core of copper,
balandron [24]

Answer with Explanation:

We are given that

Radius of  solid core wire=r=2.28 mm=2.28\times 10^{-3} m

1mm=10^{-3} m

Radius of each strand  of thin wire=r'=0.456 mm=0.456\times 10^{-3} m

Current density of each wire=J=3750 A/m^2

a.Area =\pi r^2

Where \pi=3.14

Using the formula

Cross section area of copper wire has solid core =3.14\times (2.28\times 10^{-3})^2=16.3\times 10^{-6} m^2

Current density =J=\frac{I}{A}

Using the formula

3750=\frac{I}{16.3\times 10^{-6}}

I=3750\times 16.3\times 10^{-6}=0.061 A

Total number of strands=19

Area of strand wire=A'=19\times 3.14\times (0.456\times 10^{-3})^2=12.4\times 10^{-6} m^2

J'=\frac{I'}{A'}

3750=\frac{I'}{19\times 3.14(0.456\times 10^{-3})^2}

I'=3750\times 19\times 3.14(0.456\times 10^{-3})^2

I'=0.047 A

b.Resistivity of copper wire=\rho=1.69\times 10^{-8}\Omega-m

Length of each wire =6.25 m

Resistance, R=\frac{\rho l}{A}

Using the formula

Resistance of solid core wire=R=\frac{1.69\times 10^{-8}\times 6.25}{16.3\times 10^{-6}}=6.5\times 10^{-3}\Omega

Resistance of strand wire=R'=\frac{1.69\times 10^{-8}\times 6.25}{12.4\times 10^{-6}}=8.5\times 10^{-3}\Omega

7 0
1 year ago
Points A, B, and C form the vertices of a triangle in a nonuniform electrostatic field. The electrostatic work done on a particl
Trava [24]

Answer:

Explanation:

Let electric potential at A ,B and C be Va , Vb and Vc respectively.

Work done = charge x potential difference

Wab = q ( Va - Vb )

Wac =  q (  Va -  Vc )

Given

Wac = - Wab / 3

3Wac = - Wab

Now

Wbc = q ( Vb - Vc )

= q [ ( Va-Vc ) - ( Va - Vb )]  

= Wac - Wab

= Wac + 3Wac

= 4Wac

4 0
1 year ago
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude
Pani-rosa [81]
The amplitude of a wave corresponds to its maximum oscillation of the wave itself. 
In our problem, the equation of the wave is
y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,
y(x,t)=0.750 cm
and therefore this value corresponds to the amplitude of the wave.
4 0
2 years ago
Read 2 more answers
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