An unstable nucleus which has a tendency to spontaneously change its form with the emission of high-energy particles or photons
2 answers:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct answer is option c
Explanation:
Faraday states that when there is a change in magnetic field of a coil of a wire, it means that there exist an emf in the circuit which in induced due to the change in the magnetic flux
From the question two separate but nearby coils are mounted along the axis. First coil is connected to the power supply and the current flow is controlled by the supply.When the current alternates, it would produce magnetic field ,also the second coil is connected to an ammeter which indicates the current that is flowing in it when current in the first coil changes
This magnetic field that is produce would cause a change flux which would induce current in the second coil so the ammeter would indicate current flow in the second coil
a is incorrect because the current in fir coil is not change hence flux won't change therefore current is is not induced in second coil
This is the same reason b is incorrect
d is incorrect due to the fact that when the second coil is connected to a power supply by rewiring it to be in series with first coil the law of electromagnetism would no longer hold so he ammeter would show no reading
Answer:
The options are approximations of the exact answers:
A)
B)
C)
D) Toward the inner wall
E)
Explanation:
A) The electric field in a parallel plate capacitor is given by the formula , where
and in our case
and, for air,
, so we have:
B) The K+ ion has one elemental charge excess, so its charge is , and the force a charge experiments under an electric field E is given by F=qE, so we have:
C) The potential difference between two points separated a distance d under an uniform electric potential E is given by , so we have:
D) The electic field goes from positive to negative charges, so it goes towards the inner wall.
E) The work done by an electric field through a potential difference on a charge Q is
, and is equal to the kinetic energy imparted on it, so we have: