Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
Answer:
A. 1 in. = 22.5 mi
Step-by-step explanation:
Since 22.5 x 10 = 225, we can conclude that this will fit the scale needed. B. is incorrect because it is simply illogical in context with a scale and the question. C. is incorrect since 10 x 0.04 is 0.4, which does not equal 10. D. is incorrect since we need the scale to add up to equal 225 mi, not 22.5.
Hope this helps!
Answer:
3x - 6
Step-by-step explanation:
Segment YB = x + 3
Segment BW = 2x - 9
Add the two segments.
x + 3 + 2x - 9
3x - 6
The diagonal YW is 3x - 6 units long.
Omari (3 1/2)___________(0)school____________(3 1/4)daisy
3 1/2 + 3 1/4 = 6 + (1/2 + 1/4) = 6 + (2/4 + 1/4) = 6 3/4 blocks apart <==
The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4
Therefore, the projectile stays in the air for
4 seconds
