Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
Answer
1/9
Step-by-step explanation:
the chance that she gets it one day is 1/3 so you multiply that by 1/3 because there are three days.
<span>A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b
10b = 30√2; b = 3√2
sin α = 3√2 / 6; α = 45 degrees
Small angle: 45°; Large angle: 135°</span><span>
</span>
Answer:
7
Step-by-step explanation:
8x-2y=48, replace y with 4, 8x-2(4)=48, multiply, 8x-8=48, add 8 to both sides to remove the -8, 8x=56 and finally divide by 8 to remove 8 from x, x=7.