Question

Turner's treadmill runs with a velocity of -1.3 m/s and speeds up at regular intervals during a half-hour workout. after 25 min, the treadmill has a velocity of -6.5 m/s. what is the average acceleration of the treadmill during this period ?

Answer 1

Answer:

The average acceleration of the treadmill during this period is 0.00346 m/s²

Explanation:

It is given that,

Initial velocity of the treadmill, u = 1.3 m/s

After 25 minutes, the treadmill has a velocity of 6.5 m/s

Final velocity of the treadmill, v = 6.5 m/s

Time taken, t = 25 minutes = 1500 seconds

We need to find the average acceleration of the treadmill during this period. It is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{6.5\ m/s-1.3\ m/s}{1500\ s}$

$a=0.00346\ m/s^2$

So, the average acceleration of the treadmill during this period is 0.00346 m/s². Hence, this is the required solution.

Answer 2

Given : Initial velocity = -1.3 m/s

            Final Velocity = -6.5 m/s.

            Time = 25 minutes.

To find : Average acceleration.

Solution: We are given units in meter/second (m/s).

So, we need to convert time 25 minutes in seconds.

1 minute = 60 seconds.

25 minutes = 60*25 = 1500 seconds.

Formula for average acceleration is given by,

$\frac{Final \ velocity -Initial \ velocity}{Final \ time - Initial \ time }$

We are not given intial time, so we can take initial time =0.

Plugging values in the above formula.

$Average \ acceleration = \frac{-6.5 -(-1.3)}{1500-0}$

= $\frac{-5.2}{1500}$

= -0.003467

or $Average \ acceleration = -3.467 \times 10^{-3}\ m/s^2.$.