Which formula is used to find fluctuation of the shape of body

A 3.00-kg model airplane has velocity components of 5.00 m/s due east and 8.00 m/s due north. What is the plane’s kinetic energy

GalinKa [24]

Answer:

Kinetic energy, E = 133.38 Joules

Explanation:

It is given that,

Mass of the model airplane, m = 3 kg

Velocity component, v₁ = 5 m/s (due east)

Velocity component, v₂ = 8 m/s (due north)

Let v is the resultant of velocity. It is given by :

$v=\sqrt{v_1^2+v_2^2}$

$v=\sqrt{5^2+8^2}=9.43\ m/s$

Let E is the kinetic energy of the plane. It is given by :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 3\ kg\times (9.43\ m/s)^2$

E = 133.38 Joules

So, the kinetic energy of the plane is 133.38 Joules. Hence, this is the required solution.

5 0

2 years ago

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A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel

dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

3 0

2 years ago

How many slices of bread did each climber have to eat to compensate for the increase of the gravitational potential energy of th

N76 [4]

Answer:

So No of slices to be consumed by each person = n = 65

Explanation:

Energy released by one slice = E1

$E1=10^6\ J$

h = 8850 m ; m = 79 kg ,η= 10.5%

We know that potential energy given as

u = m g h

u = 79 x 9.81 x 8850

$u=6.8\times 10^6\ J$

we know from the defination of efficiency that, η= E(out)/E(in)

Now amount of PE has to be compensated, In our case, E(out) =u

$0.105=\dfrac{E(out)}{E(in)}$

$0.105=\dfrac{6.8\times 10^6}{E(in)}$

$E(in)=64.76\times 10^6\ J$

Let n be the number of bread slices to be consumed.

n = E(in)/E1

$n=\dfrac{64.76\times 10^6}{10^6}$

n=64.76

So No of slices to be consumed by each person = n = 65

3 0

2 years ago

A man pushes a drum of oil 10kg up an incline OA. If OA is 5m and AB is 3m, what is the potential energy of the drum at A.

Paladinen [302]

Answer:

294 Joules

Explanation:

From the question;

Mass of the drum is 10 kg
The length of inclined surface, OA is 5 m
The final height of the drum on the plane AB is 3 m

We are required to determine the potential energy of the drum at A

We know that potential energy is given by the formula;

Potential energy = mgh

where m is the mass, g is the gravitational pull and h is the height

Taking g as 9.8 N/kg

Then;

Potential energy = 10 kg × 9.8 N/kg × 3 m

= 294 Joules

Thus, the potential energy of the drum at A is 294 Joules

6 0

2 years ago

Read 2 more answers

A car is traveling at 20.0 m/s on tires with a diameter of 70.0 cm. The car slows down to a rest after traveling 300.0 m. If the

cupoosta [38]

Answer: deceleration of $1.904\ rad/s^2$

Explanation:

Given

Car is traveling at a speed of u=20 m/s

The diameter of the car is d=70 cm

It slows down to rest in 300 m

If the car rolls without slipping, then it must be experiencing pure rolling i.e. $a=\alpha \cdot r$

Using the equation of motion

$v^2-u^2=2as\\$

Insert $v=0,u=20,s=300$

$0-(20)^2=2\times a\times 300\\\\a=\dfrac{-400}{600}\\\\a=-\dfrac{2}{3}\ m/s^2$

Write acceleration as $a=\alpha \cdot r$

$-\dfrac{2}{3}=\alpha \times 0.35\\\\\alpha =-\dfrac{2}{1.05}\\\\\alpha =-1.904\ rad/s^2$

So, the car must be experiencing the deceleration of $1.904\ rad/s^2$ .

4 0

2 years ago