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2 years ago

10

Explain the process of ionic bond formation between K( potassium a metal) and Br(bromine a nonmetal)

2 answers:

SVETLANKA909090 [29]2 years ago

8 0

Potassium belongs to group IA of the elements. This means that it will give up one of its electrons to form the cation K+. Opposite to that is bromine in which it accepts one electrons to form the anion Br-. The binding of these elements will form KBr and is formed from transfer of electron from one element to the other. This is the mechanism of ionic bond formation.

Ipatiy [6.2K]2 years ago

7 0

Metals transfers electrons to nonmetals. So K transfers one electron to Br because K is located at 1A in the periodic table. Br has seven electrons, now both K and Br are stable by gaining and losing one electron. <span>The transfer of electrons makes metals</span> <span>to become </span>positive ions <span>and </span>nonmetal <span>to become </span>negative ions. When a<span>n ionic bond is formed, the charges attract each other.</span>

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Answer:

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Explanation:

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So r = kq₁q₂/U

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An object of mass m has these three forces acting on it (there is no normal force, "no surface"). F1 = 1 N, F2 = 9 N, and F3 = 5

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Answer:

solved

Explanation:

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Answer:

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matrenka [14]

Answer:

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Explanation:

Hello!

To solve this problem we must use the following steps

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$R=\alpha \frac{l}{a}$

WHERE

α=

metal rod resistivity=2x10^-4 Ωm

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solving

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2. Now we model the system as a circuit with parallel resistors, where we will call 1 the metal rod and 2 the man(see attached image)

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