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2 years ago

Marissa bought 12.8 pounds of potatoes at 1.35 per pound. How much did Marissa spend for the potatoes? explain

Mathematics

1 answer:

Basile [38]2 years ago

7 0

12.8x1.35= 17.28

Marissa spent $17.28 dollars on potatoes. To find the answer you would multiply how many pounds of potatoes she want by the cost of the potatoes and that is how much Marissa spent int total.

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A symmetrical binomial distribution with large sample size can be approximated by a __________

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Typical distribution?

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2 years ago

Orin solved an equation and justified his steps as shown in the table.

sergij07 [2.7K]

Answer:

Step-by-step explanation:

Given the equation as

$\frac{3x}{5} -3=12$

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2 years ago

A local arts council has 200 members. The council president wanted to estimate the percent of its members who have had experienc

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Answer:

Yes the sample can be use to make inference

Step-by-step explanation:

The inference is possible if the conditions:

p*n > 10 and q*n > 10

where p and q are the proportion probability of success and q = 1 - p

n is sample size

Then p = 12 / 30 = 0,4 q = 1 - 0,4 q = 0,6

And p*n = 0,4 * 30 = 12 12 > 10

And q*n = 0,6 * 30 = 18 18 > 10

Therefore with that sample the conditions to approximate the binomial distribution to a Normal distribution are met

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2 years ago

Which of the following best describes the slope of the line below?

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The answer is Vertical Undefined so it's A: Undefined

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Read 2 more answers

See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se

REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 6, p = 0.2$

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015$

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064$

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564$

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if $P(X \geq 5) < 0.05$

We have that

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05$

Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

5 0

2 years ago