Question

What is the work done by a 20 newton force applied at an angle of 45.0° to move a box a horizontal distance of 40 meters? A. 8.0 × 102 joules B. 9.0 × 102 joules C. 5.6 × 102 joules D. 3.6 × 102 joules

Answer 1

Hello, Jcparris

Your answer is C. 5.6 x 102 Joules

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Answer 2

Answer:

The correct answer is option C.

Explanation:

Work done is defined as product of force applied on an object to displace it from one from position to another.

$W.D=Force\times displacement\times cos\theta$

$\theta$= Angle between the force and displacement vectors.

Force applied in the box ,F= 20N

Displacement of the box = d = 40 m

Angle between the force and displacement = $\theta =45^o$

$W.D=F.d\times \cos \theta$

$=20 N\times 40 m\times \cos (45^o)$

=$20 N\times 40 m\times 0.7071 =565.685 J\approx 5.6\times 10^2 J$

The work done is $5.6\times 10^2 J$.