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2 years ago

15

A force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s2. What

is the moment of inertia of the wheel?

1 answer:

telo118 [61]2 years ago

6 0

Answer:

4.78 kg/m^2.

Explanation:

τ = Iα

Where,

τ = torque, around a defined axis (N∙m)

I = moment of inertia (kg∙m2)

α = angular acceleration

= 1.2 rad/s^2

τ = F * r

= 16.88 * 0.34

= 5.74 N.m

Therefore, I = 5.74/1.2

= 4.78 kg/m2

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In the image attached with this answer are shown the given options from which only one is correct.

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$m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m$ This result has units of $kg$

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