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VashaNatasha [74]
2 years ago
14

Write the balanced molecular and net ionic equation for the reaction that occurs when the contents of the two beakers are added

together. (use the lowest possible coefficients. include states-of-matter under satp conditions in your answer.)
Chemistry
1 answer:
hram777 [196]2 years ago
7 0

1) hydrochloric acid with nickel:

Balanced molecular equation: Ni(s) + 2HCl(aq) → NiCl₂(aq) + H₂(g).

Ionic equation: Ni(s) + 2H⁺(aq) + 2Cl⁻(aq) → Ni²⁺(aq) + 2Cl⁻(aq) + H₂(g).

Net ionic equation: Ni(s) + 2H⁺(aq) → Ni²⁺(aq) + H₂(g).

Nickel is oxidized from oxidation number 0 (Ni) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

2) sulfuric acid with iron:

Balanced molecular equation: Fe(s) + H₂SO₄(aq) → FeSO₄(aq) + H₂(g).

Ionic equation: Fe(s) + 2H⁺(aq) + SO₄²⁻(aq) → Fe²⁺(aq) + SO₄²⁻(aq) + H₂(g).

Net ionic equation: Fe(s) + 2H⁺(aq) → Fe²⁺(aq) + H₂.

Iron is oxidized from oxidation number 0 (Fe) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

3) hydrobromic acid with magnesium :

Balanced molecular equation: Mg(s) + 2HBr(aq) → MgBr₂(aq) + H₂(g).

Ionic equation: Mg(s) + 2H⁺(aq) + 2Br⁻(aq) → Mg²⁺(aq) + 2Br⁻(aq) + H₂(g).

Net ionic equation: Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g).

Magnesium is oxidized from oxidation number 0 (Mg) to oxidation number +2, hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

4) acetic acid with zinc:

Balanced molecular equation: Zn(s) + 2CH₃COOH(aq) → (CH₃COO)₂Zn(aq) + H₂(g).

Ionic equation: Zn(s) + 2H⁺(aq) + 2CH₃COO⁻(aq) → Zn²⁺(aq) + 2CH₃COO⁻(aq) + H₂(g).

Net ionic equation: Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g).

Zinc is oxidized from oxidation number 0 (Zn) to oxidation number +2 (Zn²⁺), hydrogen is reduced from oxidation number +1 to oxidation number 0 (H₂).

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Which reaction is endothermic? HCl + NaOH Right arrow. NaCl + H2O + 58 kJ 6CO2 + 12H2O + energy Right arrow. C6H12O6 + 6O2 + 6H2
satela [25.4K]

Answer:

6CO_2 + 12H_2O + Energy->C_6H_{12}O_6 + 6O_2 + 6H_2O

Explanation:

-An endothermic reaction is a chemical reaction that gains or absorbs heat from its surrounding in the form of heat.

-During the reaction, the temperature of the surrounding reduces.

-From the reactions given:

6CO_2 + 12H_2O + Energy-> C_6H_{12}O_6 + 6O_2 + 6H_2O

is the only endothermic reaction.

6CO_2 + 12H_2O + Energy->C_6H_{12}O_6 + 6O_2 + 6H_2O

4 0
2 years ago
Read 2 more answers
Find the volume of a balloon of a gas at 842 mm Hg and -23 celcius if it’s volume is 915 milliliters at a pressure of 1170 mm Hg
Ronch [10]

The volume of a balloon f a gas at 842 mm Hg and -23 celsius if it’s volume is 915 milliliters at a pressure of 1170 mm Hg And a temperature of 24 celsius is 0.22 litres

Explanation:

Data given:

Initial volume of the balloon having gas V1= 915ml OR 0.195 L

initial pressure of the gas P1= 1170 mm Hg OR 1.53 atm

initial temperature of the gas T1 = 24 celsius or 273.15 + 24 = 297.15 K

Final pressure of the gas P2 = 842 mm Hg or 1.10 atm

final temperature of the gas T2 = -23 degrees or 273.15 - 23 = 250.15 K

Final volume at final temperature and pressure V2=?

The formula used is of Gas Law:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

putting the values in the equation:

V2 =  \frac{1.53 X 0.195 X 250.15}{297.15 X 1.10}

V2 = 0.22 litres is the volume

The volume is 0.22 litres at a pressure of 1170 mmHg and temperature of -23 degrees.

5 0
2 years ago
A mixture of CH4 and H2O is passed over a nickel catalyst at 1000 K. The emerging gas is collected in a 5.00L flask and is found
Harman [31]

Answer:

Kc =<u> 3.74*10⁻³ </u>

Kp = 25.21

Explanation:

Step 1: Data given

Temperature = 1000 K

Volume = 5.00 L

Mass of CO = 8.62 grams

Mass of H2 = 2.60 grams

Mass of CH4 = 43.0 grams

Mass of H2O = 48.4 grams

Kc = [CO]*[H₂]³ / ([CH₄]∙*H₂O])

Kp = p(CO)*p(H₂)³ / (p(CH₄)*p(H₂O) )

Step 2: The balanced equation

CH₄ + H₂O ⇄ CO + 3 H₂

Step 3: Calculate number of moles

The number of moles of each compund in the equilibrium mixture are:

Moles = mass / molar mass

n(CH₄) = 43.0g / 16g/mol = 2.688mol

n(H₂O) = 48.4g / 18g/mol = 2.689mol

n(CO) = 8.62g/28g/mol = 0.308mol

n(H₂) = 2.60g / 2g/mol = 1.3mol

Step 4: Calculate concentrations at equilibrium

So the equilibrium concentrations are:

Concentration = moles / volume

[CH₄] = 2.688mol/5L = 0.5376 M

[H₂O] = 2.689mol/5L = 0.5378M

[CO] = 0.308mol/5L = 0.0616M

[H₂) =  1.3mol/5L = 0.26M

Step 5: Calculate Kc

Kc = 0.0616 ∙ (0.26)³ / (0.5376∙0.5378) = <u>3.74*10⁻³ </u>

Step 5: Calculate partial pressure

Partial pressures in equilibrium can be found from ideal gas law:

p(X) = n(X)∙R∙T/V = [X]∙R∙T

=>  p(CH₄) = [CH₄]∙R∙T = 0.5376mol/L * 0.082 06Latm/molK ∙ 1000K = 44.11 atm

p(H₂O) = [H₂O]∙R∙T = 0.5738mol/L * 0.082 06Latm/molK * 1000K = 44.13 atm

p(CO) = [CO]∙R∙T = 0.0616mol/L * 0.082 06Latm/molK * 1000K = 5.05atm

p(H₂) = [CO]∙R∙T = 0.26mol/L * 0.082 06Latm/molK * 1000K = 21.34atm

Step 5: Calculate Kp

Kp = p(CO)*p(H₂)³ / (p(CH₄)*p(H₂O) )  

Kp = 5.05*21.34³ / (44.11*44.13 ) = 25.21

8 0
2 years ago
A gas in a rigid container at 25°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 a
m_a_m_a [10]

Gay-Lussacs law states that pressure of a gas is directly proportional to temperature when the volume is kept constant

P / T = k

where P - pressure , T - temperature in kelvin and k - constant

\frac{P1}{T1} = \frac{P2}{T2}

where parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation

T1 - 25 °C + 273 = 298 K

substituting the values in the equation

\frac{0.96 atm}{298 K}=  \frac{1.25 atm}{T2}

T2 = 388 K

temperature in celcius - 388 K - 273 = 115 °C

answer is C. 115 °C

5 0
2 years ago
Read 2 more answers
What minimum concentration of k2co3 is required to cause the precipitation of the cation that precipitates first?
Lady_Fox [76]

Answer:

The concentration is ion dependent

Explanation:

The concentration is dependent on the amount of the ions in the solution. This is the rate-determination factor. For a reaction to precipitate, there should be enough ions in the solution.  In addition, the Ksp plays an important factor in the reaction. This happens when the amount of ions formed is derived from a strong ionic solution. This then drives the reaction forward.

4 0
2 years ago
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