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2 years ago

How many electrons does it take to make 80 μc (microcoulombs) of charge?

1 answer:

6 0

The charge of a single electron is 1.602*10^ -19 C

80 µC = 8*10^ - 5 C

simple math

Total Charge / Charge of single electron = Number of electrons

(8*10^ -5 C / 1.602*10^ -19 C) = 4.99 * 10^14 electrons

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Keisha looks out the window from a tall building at her friend Monique standing on the ground, 8.3 m away from the side of the b

Salsk061 [2.6K]

Answer:

Explanation:

GIVEN DATA:

Distance between keisha and her friend 8.3 m

angle made by keisha toside building 30 degree

height of her friend monique is 1.5 m

from the figure

$\Delta ACB$

$tan 30 = \frac{8.3}{h}$

$h= \frac{8.3}{tan 30} = 14.376 m$

therefore

height of keisha is $= h + 1.5 m$

= 14.376 + 1.5

$= 15.876 \simeq 16 m$

therefore option c is correct

5 0

2 years ago

If the mass of a material is 45 grams and the volume of the material is 8 cm^3, what would the density of the material be?

Svet_ta [14]

The density of the substance is the ratio of its mass over the space it occupies. In mathematical equation, this can be expressed as,

ρ = m / v

where ρ is density, m is mass, and v is volume.

Substituting the known values from the given,

ρ = (45 g) / (8 cm³)

ρ = 5.625 g/cm³

ANSWER: 5.625 g/cm³

3 0

2 years ago

A boy uses a slingshot to launch a pebble straight up into the air. The pebble reaches a height of 37.0 m above the launch point

denis-greek [22]

Answer:

V0=27.4 m/s; t=0.8 s

Explanation:

Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:

$y_f=v_0t-0.5*g*t^2$ We solve for initial speed

$v_0=\frac{y_f+0.5gt^2}{t}=\frac{37+4.9*2.3^2}{2.3}=27.4m/s$

Now, using the same expression we estimated time to first reach 18.5 m :

$18.5=27.4t-4.9t^2$ Second order equation with solutions

t1=0.8 s and t2=4.8 s

The first time corresponds to the first reach.

7 0

2 years ago

A cylindrical specimen of brass that has a diameter listed above, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is

Irina-Kira [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The strain experienced by the specimen is 0.00116 which is option A

Explanation:

The explanation is shown on the second uploaded image

8 0

2 years ago

A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el

ollegr [7]

The answer:
the relationship between elementary charge, potential difference and electrical potential energy is given by
E= qV
E: lectrical potential energy
q: elementary charge
V: potential difference

but we have e=abs val(q)=3
so we have E= qV=3ex4.5V=13.5 eV

the answer is (4)13.5 eV

8 0

2 years ago