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Furkat [3]
2 years ago
8

If the mass of a material is 45 grams and the volume of the material is 8 cm^3, what would the density of the material be?

Physics
1 answer:
Svet_ta [14]2 years ago
3 0
The density of the substance is the ratio of its mass over the space it occupies. In mathematical equation, this can be expressed as,

        ρ = m / v

where ρ is density, m is mass, and v is volume. 

Substituting the known values from the given,
 
    ρ = (45 g) / (8 cm³)

     ρ = 5.625 g/cm³

<em>ANSWER: 5.625 g/cm³</em>
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Satellite technology has allowed us to monitor areas that were once so remote that we had no way of monitoring them. Review the
wolverine [178]

Answer: Satellite technology allows us to monitor and track the changes in the polar ice sheets. This can help us plan and direct conservation efforts for the animals that depend on polar ice in order to survive.

Explanation:

A satellite orbits around Earth. We have different satellites for different purposes. A satellite has transmitter and receiver for sending and receiving information.  For the use of environment, only one statement seems correct that is: Satellite technology allows us to monitor and track the changes in the polar ice sheets. This can help us plan and direct conservation efforts for the animals that depend on polar ice in order to survive.

Rest options are true but not from the environment point of view.

We know that animals are dependent on the environment for their survival. polar ice caps are difficult to reach and monitor. For making conservation plan for the animals residing in these remote areas, satellite technology is very crucial.

5 0
2 years ago
Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
GalinKa [24]

Answer:

The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

8 0
2 years ago
An escaped convict runs 1.70 km due East of the prison. He then runs due North to a friend's house. If the magnitude of the conv
olga2289 [7]

Answer:

The right approach will be "47° north of east".

Explanation:

The given values are:

East of prison

= 1.70 km

Displacement vector

= 2.50 km

Now,

The direction will be:

⇒  Cos \ \theta =\frac{1.7}{2.5}

⇒            =0.68

⇒         \theta=47.16^{\circ}

i,e.,       \theta = 47^{\circ} (north of east)

6 0
2 years ago
The drag force F on a boat varies jointly with the wet surface area A of the boat and the square of the speed s of the boat. A b
Advocard [28]

Answer:

Wet surfaces areaA=+25.3ft^2

Explanation:

Using F= K×A× S^2

Where F= drag force

A= surface area

S= speed

Given : F=996N S=20mph A= 83ft^2

K = F/AS^2=996/(83×20^2)

K= 996/33200 = 0.03

1215= (0.03)× A × 18^2

1215=9.7A

A=1215/9.7=125.3ft^2

7 0
2 years ago
Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p
makvit [3.9K]
We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space). 

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
<span>= 4•3 = 12.</span>
5 0
2 years ago
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