Question

The slope intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope form of the equation for this line?

Answer 1

y + 13 = 5x + 10

the equation of a line in ' point- slope form ' is

y - b = m(x - a) (m is the slope and (a, b ) a point on the line )

from y = 5x - 3 we  obtain m = 5 and (a, b ) = ( - 2, - 13 )

y + 13 = 5(x + 2) in point- slope form

Answer 2

Answer: $(y+13)=5(x+2)$

Step-by-step explanation:

The equation of a line in intercept form is given by:-

$y=mx+x$, where m is the slope of line .

Comparing given equation $y = 5x -3$ to above equation, we get

Slope : m= 5

The point slope form of a line with slope m that passes through point (a,b) is given by :-

$(y-b)=m(x-a)$

Thus , the point slope form of the equation for this line with slope 5 and asses through point (-2, -13) will be :-

$(y-(-13))=5(x-(-2))$

$(y+13)=5(x+2)$