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SIZIF [17.4K]
2 years ago
13

Vector A⃗ points in the negative y direction and has a magnitude of 7 units. Vector B⃗ has twice the magnitude and points in the

positive x direction.
Find the direction and magnitude of A⃗ +B⃗ .
Express your answer as a whole number.

Physics
2 answers:
Sergeu [11.5K]2 years ago
3 0
So vector A has a magnitude of 7 units in the negative Y direction and the Vector B has a magnitude of 14 units in the positive x. Which means that A has a coordinate of A(0,-7) nad B is B(14,0).

-The direction and the magnitude of A+B is -7 down and 14 forward

o-na [289]2 years ago
3 0

The magnitude of the vector (\vec A+\vec B) is \boxed{16 \text{ units}} and the direction of the vector (\vec A+\vec B) is \boxed{26.56^\circ\text{ anticlockwise}}

Further Explanation:

\Vec A points in the negative Y-direction and has a magnitude of 7\text{ units}, so we will show it as a line of length 7\text{ units} in negative Y-direction.

\Vec B has twice the magnitude and points in the positive X-direction, so we will show it by a line of double the length as before in positive X-direction, as shown in the figure below.

According to Cartesian coordinate system, the resultant will start either from tail of \vec A and ends at head of \vec B and vice-versa.

Now, resultant will be given by  

\begin{aligned}\vec R&=\vec A+\vec B\\\vec R&=({-7\hat j+14\hat i})\\\end{aligned}

Hence, the magnitude of resultant or of vector \vec A + \vec B is given by:

\begin{aligned}|{\vec R}|&=\sqrt{({7^2}+{14^2})}\\&=\sqrt{(49+196)}\\&=\sqrt{245}\\&=15.65{\text{ units}}\\\end{aligned}

It can be expressed in whole number as:

\boxed{|\vec R|=16\text{ units}}

Now, the direction of the resultant vector \vec R or of the vector \vec A + \vec B is given by:

\tan\theta=\dfrac{{|{\vec A}|}}{{|{\vec B}|}}

Now, substituting the values of vector \vec A and \vec B:

\begin{aligned}\tan\theta&=\dfrac{7}{{14}}\\\tan\theta&=0.5\\\theta&={\tan^{-1}}(0.5)\\&=\boxed{26.56^\circ}\\\end{aligned}

Thus, the magnitude of the vector (\vec A+\vec B) is \boxed{16 \text{ units}} and the direction of the vector (\vec A+\vec B) is \boxed{26.56^\circ\text{ anticlockwise}}

Learn More:

1. A vector A is added to B= 6i-8j brainly.com/question/5892298

2. A head-on elastic collision between two particles brainly.com/question/6439920

3. An astronaut takes her bathroom scale on moon where g=1.6 m/s2 brainly.com/question/11292757

Answer Details:

Grade: High School

Subject: Physics

Chapter: Vectors and Scalars

Keywords:

Vector, scalars, vector A, Vector B, addition, resultant, unit, magnitude, direction, positive, X-axis, Y- axis, negative, 7 units, 14 units, twice the magnitude.

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2 years ago
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Explanation:

Look at the attached graphic

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Calculation of the components of equilibrant force (Fe)

the x-y components of the  equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

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Calculation of the direction of  equilibrant force (α)

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Look at the attached graphic

6 0
2 years ago
Una cuerda de violin vibra con una frecuencia fundamental de 435 Hz. Cual sera su frecuencia de vibracion si se le somete a una
EleoNora [17]

Answer:

a)  f = 615.2 Hz      b)  f = 307.6 Hz

Explanation:

The speed in a wave on a string is

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also the speed a wave must meet the relationship

          v = λ f

           

Let's use these expressions in our problem, for the initial conditions

            v = √ T₀ /μ

             √ (T₀/ μ) = λ₀ f₀

now it indicates that the tension is doubled

         T = 2T₀

          √ (T /μ) = λ f

          √( 2To /μ) = λ f

         √2  √ T₀ /μ = λ f

we substitute

         √2 (λ₀ f₀) = λ f

if we suppose that in both cases the string is in the same fundamental harmonic, this means that the wavelength only depends on the length of the string, which does not change

           λ₀ = λ

           f = f₀ √2

           f = 435 √ 2

           f = 615.2 Hz

b) The tension is cut in half

         T = T₀ / 2

         √ (T₀ / 2muy) =  f = λ f

          √ (T₀ / μ)  1 /√2 = λ f

           fo / √2 = f

           f = 435 / √2

           f = 307.6 Hz

Traslate

La velocidad en una onda en una cuerda es

         v = √ T/μ

ademas la velocidad una onda debe cumplir la relación

          v= λ f  

           

Usemos estas expresión en nuestro problema, para las condiciones iniciales

            v= √ To/μ

             √ ( T₀/μ) = λ₀ f₀

ahora nos indica que la tensión se duplica

         T = 2T₀

          √ ( T/μ) = λf

          √ ) 2T₀/μ = λ f

         √ 2 √ T₀/μ = λ f

         

substituimos  

         √2    ( λ₀ f₀)  =  λ f

si suponemos que en los dos caso la cuerda este en el mismo armónico fundamental, esto es que la longitud de onda unicamente depende de la longitud de la cuerda, la cual no cambia

                 λ₀ =  λ

           f = f₀ √2

           f = 435 √2

           f = 615,2 Hz

b)  La tension se reduce a la mitad

         T = T₀/2    

         RA ( T₀/2μ)  =  λ  f

          Ra(T₀/μ) 1/ra 2  =  λ f

           fo /√ 2 = f

           f = 435/√2

           f = 307,6 Hz

5 0
1 year ago
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