Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
I'm going to assume you meant to write fractions (because if 
are all non-negative integers, the series would clearly diverge), so that
and so on.
a. If the pattern continues as above, we would have the general term
b. Note that we can write as
The series diverges by comparison to the divergent series
3 gardeners :90 minutes
? Gardeners : 15 minutes
1 gardener : 270 minutes
? Gardeners : 270/15
18 gardeners
Answer:
Step-by-step explanation:
Given the function is 
........... (1)
Now, we are given that 
.......... (2)
Now, the left hand side of both the above equations (1) and (2) are similar and the only change is that t is replaced by 4a.
Therefore, the equation (2) can be written as
(Answer)
Since we know that if then 
, where k is any real value.
Answer: 
Step-by-step explanation:
We have two circles:
Cirlce 1, with a radius 
and area 
:
And Cicle 2, with a radius 
and area 
:
Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:
Finally:
