Hello from MrBillDoesMath!
Answer:
669/221
Discussion:
Ratio of 669 to 221 = 669/221.
Now, 669 = 3 * 223 and 221 = 13 * 17. Note that all numbers involved in the factorizations are distinct primes so nothing cancels out in their ratio. That is,
669/221 can not be reduced further.
Thank you,
MrB
If all the flags use material at the same rate, Nancy will need 3 times the fabric to make 3 times the number of flags. Nancy needs 3×(14 yd) = 42 yd for the whole team.
Answer:
Length = 5p + 3
Perimeter = 26p + 6
Step-by-step explanation:
Given
Area = 40p² + 24p
Width = 8p
Solving for the length of deck
Given that the deck is rectangular in shape.
The area will be calculated as thus;
Area = Length * Width
Substitute 40p² + 24p and 8p for Area and Width respectively
The formula becomes
40p² + 24p = Length * 8p
Factorize both sides
p(40p + 24) = Length * 8 * p
Divide both sides by P
40p + 24 = Length * 8
Factorize both sides, again
8(5p + 3) = Length * 8
Multiply both sides by ⅛
⅛ * 8(5p + 3) = Length * 8 * ⅛
5p + 3 = Length
Length = 5p + 3
Solving for the perimeter of the deck
The perimeter of the deck is calculated as thus
Perimeter = 2(Length + Width)
Substitute 5p + 3 and 8p for Length and Width, respectively.
Perimeter = 2(5p + 3 + 8p)
Perimeter = 2(5p + 8p + 3)
Perimeter = 2(13p + 3)
Open bracket
Perimeter = 2 * 13p + 2 * 3
Perimeter = 26p + 6
Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.
cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.
Now we have to determine, Can he build a shed that is twice as high as it is wide.
that means if width is 1 then height should be twice which is 2.
yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.
Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."
