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2 years ago

43/19 as a decimal rounded to the nearest hundreth

Mathematics

2 answers:

Lesechka [4]2 years ago

6 0

use calculator to get 43/19=2.263157...

rounded to the nearest hundredth: 2.26

frutty [35]2 years ago

3 0

Answer:

2.26

Step-by-step explanation:

We have been given a fraction $\frac{43}{19}$ . We are asked to find decimal value of our given expression rounded to the nearest hundredth.

Upon simplifying our given fraction, we will get:

$\frac{43}{19}=2.2631578947368421$

To round our answer to nearest hundredth, we will round our answer to 2 digits after decimal. We can see that thousandth value is less than 5 that is 3, so will keep last digit 6 as:

$\frac{43}{19}\approx 2.26$

Therefore, the decimal value of our given fraction is approximately 2.26 to the nearest hundredth.

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Which of the following is a point of tangency on the circle below?<br> Help ASAP please

kumpel [21]

Answer:

Point B

Step-by-step explanation:

a point of tangency on a circle is where an outside line touches the outer circle at one point (the outside line touching it only once is what makes that line a tangent) so in this case the point of tangency is Point B

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6 0

2 years ago

The enrollment at sunshine College has been increased by 45 students per year. Currently sunshine College has 1100 students atte

docker41 [41]

Answer:

After 15 years both the colleges will have same number of students.

Step-by-step explanation:

The enrollment at sunshine College has been increased by 45 students per year. Currently, sunshine College has 1100 students attending.

So, after x years the number of students of this college will be (1100 + 45x).

Again, Marigold college currently has 2000 students, but its enrollment is decreasing in size by an average of 15 students per year.

So, after x years the number of students of this college will be (2000 - 15x).

If those two colleges have the same number of students after x years, then we can write

1100 + 45x = 2000 - 15x

⇒ 60x = 900

⇒ x = 15 years.

Therefore, after 15 years both the colleges will have the same number of students. (Answer)

7 0

2 years ago

"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt

Westkost [7]

Answer:

a) $\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})$

b) $Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5$

c) $P(\bar X >31.25)=0.006=0.6\%$

d) $P(\bar X >28.25)=0.9997=99.97\%$

e) $P(28.25$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

$X\sim N(\mu =30,\sigma =2)$

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is also normal and is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})$

b. What is the standard error of the mean time?

The standard error is given by this formula:

$Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5$

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

And we want to find this probability:

$P(\bar X >31.25)=1-P(\bar X$

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

And we want to find this probability:

$P(\bar X >28.25)=1-P(\bar X$

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

$P(28.25$

3 0

2 years ago

3 A buoy is 30 feet from the shore. You swim 3/5 the way to the buoy. How much farther do you have to swim to reach the buoy?

disa [49]

Answer:

12 feet

Step-by-step explanation:

30 divided by 5= 6

6 times 3= how far youve already swam(18 feet)

6 times 2= how far you have left(12 feet)

8 0

2 years ago

Jana is prescribed 250 mg of medication. Seventy-five percent of the medication remains in her body after each hour, h, accordin

SOVA2 [1]

Jana was prescribed medication. m = 250(0.75)^h

6 hours after Jana took her medication, Allison was prescribed the same.
m=250(0.75)^(h-6)

<span>At any time after she has taken the medication, Allison has how many times more milligrams of medication in her body?
</span>
Same with Jana, Allison's medication content in her body will decrease by 25% after each hour.

Let h = 6

Jana: m = 250(0.75)^6 = 250(0.178) = 44.50
Allison: m = 250(0.75)^6-6 = 250(1) = 250

250 - 44.50 = 205.50

On hour 6, Allison will have 205.5 mg more of the medicine than Jana.

7 0

2 years ago

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