Person A buys 10 granola bars and 6 cups of yogurt for <em>$18</em>
Person B buys 5 granola bars and 4 cups of yogurt for <em>$9.50</em>
Let <u>x</u> represent the granola bars
Let <u>y</u> represent the yogurt
10x + 6y = 18 << ( Divide both sides by 2 )
The second equation is 5x + 4y = 9.50. Now subtract the two equations.
5x + 4y = 9.50
-5x - 3y = -9
y = $.50
5x + 3(.50) = 9
5x + 1.50 = 9
5x = 7.5
x = $1.50
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Answer:
q1=11
q3= 33
Step-by-step explanation:
The data set has 44 number of students. The first quartile is 25 % of the numbers in the data set . So
25 % of 44 = 25/100 * 44= 0.25 *44 = 11
So the first quartile lies at 11.
Similarly the third quartile lies at the 75 % of the numbers of the data set . So
75 % of 44 = 75/100 * 44= 0.75 *44 = 33
So the third quartile lies at 33.
Answer:
327.4
Step-by-step explanation:
All you have to do to simplify a number written in scientific notation is to move the decimal place to the left (if the number is negative) and to the right (if the number is positive).
Answer:
0.15c-0.072
divide both side by 0.15c
then simplify by the answer then you will get your answer
Step-by-step explanation:
0.15c-0.072
divide both side by 0.15c
then simplify by the answer then you will get your answer
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = 
= 15°c
The final temperature = 
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( - )
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
