Given f(x)=3x²-5x-2
a) To find f(a+h) replace x with a+h in the given function. So,
f(a+h)=3(a+h)²-5(a+h)-2
=3(a²+2ah+h²)-5(a+h)-2 By using the formula (x+y)²=x²+2xy+y².
=3a²+6ah+3h²-5a-5h-2 By distributing property.
b) Similarly to find f(a) we need to replace x with a. So,
f(a)=3a²-5a-2
So, f(a+h)-f(h)= (3a²+6ah+3h²-5a-5h-2)-(3a²-5a-2)
=3a²+6ah+3h²-5a-5h-2-3a²+5a+2.
=6ah+3h^2-5h (All other terms has been cancel out)
Answer:
10,346.0(1.1)^x
112,096 people
Step-by-step explanation:
edg
1.5r+15=2.25r
First of all, you have to arrange the numbers according to those similar to them. So that will be;
15=2.25r-1.5r
1.5r is subtracted from 2.25r because it crossed over an equality sign to get its position close to 2.25r. And when a number crosses over an equality sign, the sign on the number chages to the opposite. 1.5r has an invisible positive sign which became negative when it crossed. Anyway;
2.25r-1.5r is the same as 2.25-1.5. And that is 0.75r
Therefore;
15=0.75r
To find out what r is, you have to divide the both sides by 0.75. This is done to remove the 0.75 close to r to finally reveal what r is. Anyway;
15/0.75=0.75r/0.75
15 divided by 0.75 is 20. And 0.75r divided by 0.75 is r. So;
20=r
r=20. So the answer is 20 movies. Hope i helped. Have a nice day.
Answer:
Here we have given two catogaries as degree holder and non degree holder.
So here we have to test the hypothesis that,
H0 : p1 = p2 Vs H1 : p1 not= p2
where p1 is population proportion of degree holder.
p2 is population proportion of non degree holder.
Assume alpha = level of significance = 5% = 0.05
The test is two tailed.
Here test statistic follows standard normal distribution.
The test statistic is,
Z = (p1^ - p2^) / SE
where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]
p1^ = x1/n1
p2^ = x2/n2
p^ = (x1+x2) / (n1+n2)
This we can done in TI_83 calculator.
steps :
STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER
Test statistic Z = 1.60
P-value = 0.1090
P-value > alpha
Fail to reject H0 or accept H0 at 5% level of significance.
Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.
ANSWER
The set of all rational numbers and the set of all real numbers.
EXPLANATION
The set of rational numbers contains all numbers that can be written in the form,
where a and b are integers and b≠0.
The given number is
It belongs to the set of rational numbers.
The set of rational numbers is a subset of the set of real numbers.
Hence
also belongs to the set of real numbers.
The correct answer is A.
