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dlinn [17]
2 years ago
13

A 7.5 kg cannon ball leaves a canon with a speed of 185 m/s. Find the average net force applied to the ball if the cannon muzzle

is 3.6 m long.
Physics
1 answer:
schepotkina [342]2 years ago
5 0

We would like to know the average net force. Therefore, we can calculate the acceleration using:

x = 0.5*a*t^2

v = a*t

where x=3.6m and v=185 m/s.

Therefore,

t=v/a     and hence    x = 0.5*a*(v/a)^2 = 0.5 * (v^2)/a

so    a= (0.5*v^2)/x

Since we know the values for v and x, as written above, we can calculate a by plugging the numbers in.

The average net force will then be:

F = m*a,

where m=7.5kg.


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Calculate the Engineering Ultimate Tensile Strength and the maximum load in tension testing of an annealed copper specimen with
Natasha_Volkova [10]

Answer:

Explanation:

Original diameter = 5mm

d= 0.005m. r=0.0025m

True stress (σ) = 290MPa

Coefficient of annealing copper (n)=0.5

True stress is given as force/area

σ=F/A

Ao=πr^2

Ao=1.963×10^-5m2

F=σ ×A

F=290×10^6 ×π×(0.0025)^2

F= 5694.13N

Given that

σ=Kε^n

290=Kε^0.5

n=ε=0.5 at necking

Therefore

290=K×0.5^0.5

K=410.12MPa

ε=In(Ao/A)

0.5=In(π×0.0025^2/A)

exp(0.5)=1.96×10^-5/A

A=1.96×10^-5/exp(0.5)

A= 1.2×10^-5m2

This is the new area

Then the Ultimate Tensile Stress

σ=F/A

σ=5694.13/1.2×10^-5

σ=4.75×10^8Pa

σ=475MPa

Therefore,

The ultimate tensile stress is 475MPa.

The maximum tension is

Fo/Ao=F/A

F=(Fo/Ao) ×A

F=(5694.13/1963×10^-5)×1.2×10^-5

F= 3479.99

F=3480N.

3 0
2 years ago
One kind of slingshot consists of a pocket that holds a pebble and is whirled on a circle of radius r. The pebble is released fr
Debora [2.8K]

Answer:

θ=142.9°

Explanation:

d=1 *r

angle ϕ= 37.1°

the line connecting pebble and target should be tangent to a circle so

cos(180-ϕ-θ)=\frac{r}{d}=\frac{1}{1}

∴ θ=180-ϕ-cos^{-1} (\frac{1}{1} )

  θ= 180-37.1-0

  θ=142.9°

 

5 0
2 years ago
A proton travels at right angles through a magnetic field of 0.025 teslas. If the magnitude of the magnetic force on the proton
lapo4ka [179]

Answer:

v = 4.50 x 10^6 m/s\\

Explanation:

8 0
2 years ago
a driver shifts into neutral when her 1200 kg is moving at 80 km/h and finds the speed has dropped to 65 km/h 10 s later . what
Liono4ka [1.6K]
Drag<span> is a </span>force<span> acting opposite to the relative motion of any object moving. It can be calculated as follows:

</span><span><span>vi </span>= (<span><span>80km/</span><span>hr) (1</span></span><span><span>hr / </span><span>3600sec) (</span></span><span><span>1000m/</span><span>1km) </span></span>= <span><span>22.2 m/</span>sec

</span></span> <span><span>vf</span>= (<span><span>65km/</span><span>1hr) (</span></span><span><span>1hr/</span><span>3600sec) (</span></span><span><span>1000m/</span><span>1km) </span></span>= <span><span>18.06 m / </span>sec</span></span> <span>
a=<span><span><span>vf</span>−<span>vi / </span></span><span><span>tf</span>−<span>ti = </span></span></span><span><span>18.06m/s−22.2m/s / </span><span>10sec−0sec</span></span>= <span><span>−0.414m</span><span>sec2

</span></span></span><span>F = ma = 1200kg×<span><span>−0.414m</span><span>s2 </span></span>= −496.8N</span>
6 0
2 years ago
The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang
STatiana [176]

the correct answers are 54N and -1,2m/s^2

6 0
2 years ago
Read 2 more answers
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