A. The penny experienced a color change, and a gas was produced.
The penny was less tarnished (color change), and tiny bubbles formed around the penny (due to a gas being produced).
Answer:
Dipole-Dipole attraction
Explanation:
Dipole-dipole attraction is a type of vander waals forces found in the molecules of sulfur dioxide.
Vander waals forces are weak attractions joining non-polar and polar molecules together. They are of two types:
- London dispersion forces which are weak attractions found between non-polar molecules.
- Dipole-Dipole attraction are the forces of attraction which exists between polar molecules. Such molecules have permanent dipoles. This implies that the positive pole of one molecule attracts the negative pole of another. This is what happens between the oxygen and sulfur molecules.
Answer:
c. Bomb calorimetry
Explanation:
The hydrocarbons are combustibles, it means that they can react in a combustion reaction to release energy. To measure this amount of energy, it's necessary equipment that the reaction can be placed in a controlled way. The bomb calorimeter is this equipment, which is an adiabatic vessel, with water. The heat is calculated based on the increase in the water temperature.
The coffee-cup calorimetry is used to measure the heat of a dissolution reaction and the bomb manometry is used to measure the pressure.
Answer:
50 g of S are needed
Explanation:
To star this, we begin from the reaction:
S(s) + O₂ (g) → SO₂ (g)
If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.
According to stoichiometry, we can determine the moles of sulfur dioxide produced.
100 g. 1mol / 64.06g = 1.56 moles
This 1.56 moles were orginated by the same amount of S, according to stoichiometry.
Let's convert the moles to mass
1.56 mol . 32.06g / mol = 50 g
Answer: The reaction is not at equilibrium and will proceed to make more products to reach equilibrium.
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium, while Q is the reaction quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
For the given chemical reaction:
The expression for 
is written as:
![Q=\frac{[HI]^2}{[H_2]^1[I_2]^1}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5E1%5BI_2%5D%5E1%7D)
![Q=\frac{[0.0890]^2}{[0.215]^1[0.498]^1}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5B0.0890%5D%5E2%7D%7B%5B0.215%5D%5E1%5B0.498%5D%5E1%7D)
Given : = 54.8
Thus as 
, the reaction will shift towards the right i.e. towards the product side.
