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sertanlavr [38]
2 years ago
4

The chart shows information about four ecosystems. Ecosystem Data Ecosystem Average Year-Round Temperature (°F) Niche Diversity

Size (square miles) W 35 medium 140 X 74 high 100 Y 46 high 75 Z 87 low 60 Based on the information in the chart, which ecosystem most likely has the highest biodiversity? W X Y Z
Chemistry
2 answers:
vladimir2022 [97]2 years ago
8 0

The correct answer is option <u><em>B) X</em></u>

I just did the quiz and put Z smh but I got it wrong and the correct one was X.

Hope this helps and have a grr8 day buds <3

ruslelena [56]2 years ago
7 0

Answer:

The answer is x

Explanation:

X 74

hope this helps

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We have an object with a density of 620 g/ cm3 and a volume of 75 cm3. What is the mass of this object?
Anna11 [10]
M=D*V
D=620 g/cm³
V=75 cm³

m= 620 g/cm³ * 75 cm³=46500 g
m=46500g
8 0
2 years ago
Which mass of gas would occupy a volume of 3dm3 at 25°C and 1 atmosphere pressure?
balu736 [363]

Answer:

C 8.09 SO2 gas

Explanation:

As we have the volume (3dm³ = 3L), temperature (25°C + 273 = 298K), and pressure (1atm), we can solve to moles of gas using:

PV = nRT

PV / RT = n

1atm*3L / 0.082atmL/molK*298K =¨

0.123 moles of gas you have.

Now, to convert these moles to mass we use molar mass (32g/mol for O2, 28g/mol for N2, 64g/mol for SO2, and 44g/mol for CO2).

Mass of 0.123 moles of these gases is:

O2 = 0.123 moles * 32g/mol = 3.94g of O2. A is wrong

N2 = 0.123 moles * 28g/mol = 3.4g of N2. B is wrong

SO2 = 0.123 moles * 64.1g/mol = 7.9g of SO2≈ 8.09g of SO2, C is possible

CO2 = 0.123 moles * 44g/mol = 5.4g of CO2. D is wrong

Right answer is:

<h3>C 8.09 SO2 gas </h3>

8 0
2 years ago
Why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.
drek231 [11]
Net Primary Productivity ... the amount of biomass present in an ecosystem at a particular time .... Explain why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.
8 0
2 years ago
A compound has the name iodine pentafluoride. What kind of bond is present between the atoms? A. O Metallic B Covalent C. Hydrog
8090 [49]

Answer:

IF(subscript 5)

Explanation:

covalent.

3 0
1 year ago
How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?
mash [69]

Answer : Both solutions contain 3.011 X 10^{23} molecules.

Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain 3.011 x 10^{23} molecules.

Avogadro's Number is  N_{A} =  6.022 X 10^{23} which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.

Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.

Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.

Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.

We can calculate the number of molecules for each;

Number of molecules  = N_{A} X M;

∴  Number of molecules =  6.022 X 10^{23} X 0.5 mol/L X 1 L which will be  = 3.011 X 10^{23}

Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.

7 0
2 years ago
Read 2 more answers
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