Answer:
• Because the sets are not symmetrical, the IQR should be used to compare the data sets.
• Because the sets contain outliers, the median should be used to compare the data sets.
• The mean and mode cannot be accurately determined based on the type of data display.
Step-by-step explanation:
When we observe the set of given data above, we can denote that the data obtained by comparing the height of students from class 1 and class 2 would not be similar hence we can say this obtained data is not symmetrical.
Due to the fact that this data is is obtained from different classes it is certain that there would be variations in the data when measuring the heights of the students and an error may occurs. These variations are referred to as OUTLIERS.
Therefore, Median or Interquartile range is the appropriate measure to be used for comparing the data sets.
Answer:
Given Below
Step-by-step explanation:
v = u+at
u+at = v
at = v-u
t = v-u/a
Hope this helps
Answer:
error in step 1
Step-by-step explanation:
well where is does the step not make sense?
remember cos(pi) = -1 and sin(pi)=0
that means step 1 is strange... it didn't distribute properly
it should have been:
cos(pi) - cos(A)
hope that helps! ^-^
Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), 
.
With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.
