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nika2105 [10]
2 years ago
10

You and a friend each have a collection of tokens. Initially, for every 8 tokens you had, your friend had 3. After you give half

of your tfriend, your friend now has 18 more tokens than you. Initially, how many more tokens did you have than your friend
Mathematics
1 answer:
Sonbull [250]2 years ago
6 0

Answer: 30 token

Step-by-step explanation:

Since, according to the question,

Initially, for every 8 tokens I had, my friend had 3.

Therefore, ratio of tokens that me and my friend is  8 : 3

Let I have 8 x tokens and my friend has 3 x tokens, where x is any number.

Then again according to the question,

After I gave half of your friend, my friend now has 18 more tokens than you.

That is, (3x + 4x) - 4x = 18

⇒ 7x - 4x = 18

⇒ 3x = 18

⇒ x = 6

Therefore , Initially the difference between me and my friend's token = 8 x - 3 x = 5 x = 5 × 6 = 30


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Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

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Now according to given condition we have

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\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

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Answer:

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Step-by-step explanation:

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