A sideways opening parabola is in the form
, so we know from the process of elimination that it will either be b or c. Next we have to realize that if the parabola opens to the left it is a negative parabola, just like if a parabola opens upside down it is a negative parabola. So the one that has the negative out front is b.
Answer: B: n^2+6n+1
Step-by-step explanation:
A=n
B=2n+6
C=n^2-1
AB-C
n(2n+6)-n^2-1
2n^2+6n-n^2+1
n^2+6n+1
Answer:
b ) the intersection of two events
Step-by-step explanation:
Gary and Steve are both hosting . There are 50 buttons total, 15 buttons are blue and 27 buttons are red. Gary puts all of the buttons into a bag. Steve and Gary both want to wear red buttons.What is the probability ? To solve this problem, you need to understand the Multiplication Rule of Probability.This probability means to find the probability of the intersection of two events, multiply the two probabilities.
Probability of two events occurring that is called intersection of two events. There are two different set of events , called independent and dependent events.
Independent events event is not affected by a previous event.
A dependent event is when one event influences the outcome of another event . To find the intersection of two events, whether they are independent or dependent, multiply the two probabilities together.
<span>What is r = wp, for p
</span>r = wp...divide both sides by w
so then p = r/w
Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot
answer : The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )
Step-by-step explanation:
The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship
<em>A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship </em>
