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Olenka [21]
2 years ago
13

Imagine you’re driving along a road and you approach a bridge. You notice a sign that reads, “Bridge freezes before road.” Why d

o bridges become covered with ice before roads do? Research this question and respond in depth, writing a full paragraph. Be sure to include examples. At the end of your response, provide at least two authoritative sources that you used in your research.
Physics
2 answers:
Nataly [62]2 years ago
6 0

Bridge freeze before road because of two reasons:

1. Bridge are exposed to environment from all sides. That is why they are more prone to temperature decrease. While roads are only exposed fro top, they are least prone to the environment as compare to bridges.

2. Bridge have more surface area for heat loss. While, road have lesser area available for heat loss.

Sources:

https://wonderopolis.org/wonder/why-do-bridges-freeze-before-roads

http://wxguys.ssec.wisc.edu/2011/02/28/why-do-bridges-ice-before-the-road/

http://icyroadsafety.com/icybridges.shtml

adell [148]2 years ago
4 0

Answer:

Bridges are exposed to more environmental factors than typical roadways are. This is because the roads are built on top of the ground, leaving typical road exposure only on the surface and what very little part of the side is raised higher than the ground and therefore exposed. Bridges are exposed to the elements from all sides. They are also typically built over wet areas, increasing their exposure to the elements through “sea breezes.” They are not subject to any geothermal heating that typical roadways are exposed to. The earth under normal road ways absorbs heat and warm ups, then release heat which keeps the ground warm for a while. Bridges do not have this type of insulation. When freezing rain falls over a roadway and a bridge at the same time, the bridge is the same temperature as the air and is prone to freezing almost as quickly as the rain. Environmental factors from the surrounding area under the bridge can also cause the bridge to freeze more quickly. Fog, mist, and cooler temperature from the surrounding water lower the temperature of the bridge. Metal also cools down faster than tar itself. They are prone to temperature decreases simply because they have more surface area for heat loss. Typical roadways are less prone to this type of cooling or this amount of cooling.  

Sources:

http://icyroadsafety.com/icybridges.shtml

https://science.howstuffworks.com/nature/climate-weather/atmospheric/question566.htm

Explanation:

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wheel rotates from rest with constant angular acceleration. Part A If it rotates through 8.00 revolutions in the first 2.50 s, h
Alex73 [517]

Answer:

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

Explanation:

Given;

wheel rotates from rest with constant angular acceleration.

Initial angular speed v = 0

Time t = 2.50

Distance x = 8 rev

Applying equation of motion;

x = vt +0.5at^2 ........1

Since v = 0

x = 0.5at^2

making a the subject of formula;

a = x/0.5t^2 = 2x/t^2

a = angular acceleration

t = time taken

x = angular distance

Substituting the values;

a = 2(8)/2.5^2

a = 2.56 rev/s^2

velocity at t = 2.50

v1 = a×t = 2.56×2.50 = 6.4 rev/s

Through the next 5 second;

t2 = 5 seconds

a2 = 2.56 rev/s^2

v2 = 6.4 rev/s

From equation 1;

x = vt +0.5at^2

Substituting the values;

x2 = 6.4(5) + 0.5×2.56×5^2

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

5 0
2 years ago
Which equation is most likely used to determine the acceleration from a velocity vs:time graph?
tresset_1 [31]
Acceleration, a =  (v - u)/t

where v is the final velocity, u is the initial velocity, and t is the time.

This formula on a velocity time graph represents the slope of the graph.
 
7 0
2 years ago
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If you find an igneous rock which has 450 radioactive isotopes and 3,150 stable daughter isotopes, how many half-lifes of this i
slavikrds [6]

Answer:

3t_{1/2}  

Explanation:

To find the half-lifes of the isotope we need to use the following equation:

N_{t} = N_{0}2^{-\frac{t}{t_{1/2}}}     (1)

<em>where Nt: is the amount of the isotope that has not yet decayed after a time t, N₀: is the initial amount of the isotope, t: is the time and </em>t_{1/2}<em>: is the half-lifes.</em>

By solving equation (1) for t we have:

\frac{t}{t_{1/2}} = - \frac{Ln(Nt/N_{0})}{Ln(2)}

<u>Having that:</u>

Nt = 450

N₀ = 3150 + 450 = 3600,

The half-lifes of the isotope is:

t = - \frac{Ln(450/3600)}{Ln(2)} \cdot t_{1/2} = 3t_{1/2}

Therefore, 3 half-lives of the isotope passed since the rock was formed.

I hope it helps you!

3 0
2 years ago
An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir
Natalija [7]

A photoelectric cell is an electronic device which is used to convert light energy into electric energy.The operation of this device is based on photoelectric effect.

Light of suitable frequency i.e greater or equal to threshold frequency will fall on the cathode maintained at negative potential.The electron emission will take place and these electrons are drifted towards the anode which is at positive potential.

Here,only those radiations will be capable of emitting electrons irrespective of surface barrier of metals whose energy is greater than the work function.

We know that the radiation having long wavelength has least energy as energy and wavelength are inversely proportional to each other.

Mathematically\ energy\ E=\frac{hc}{\lambda}

Here h is the Planck's constant,c is the velocity of light.

Here we have been given red light and blue light.

In the visible spectrum of radiation, the red light has longer wavelength than all other colors of light.Hence blue light has more energy as it's wavelength is less as compared to red light.

Hence, the blue light will activate the most and red the least.

3 0
2 years ago
Read 2 more answers
The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente
kipiarov [429]

Answer:

I=68.31\times 10^{-6}\ A

Explanation:

Given that

J(r) = Br

We know that area of small element

dA = 2 π dr

I = J A

dI = J dA

Now by putting the values

dI = B r . 2 π dr

dI= 2π Br² dr

Now by integrating above equation

\int_{0}^{I}dI= \int_{r_1}^{r_2}2\pi Br^2 dr

I={2\pi B}\times \dfrac{r_2^3-r_1^3}{3}

Given that

B= 2.35 x 10⁵ A/m³

r₁ = 2 mm

r₂ = 2+ 0.0115 mm

r₂ = 2.0115 mm

I={2\pi B}\times \dfrac{r_2^3-r_1^3}{3}

By putting the values

I={2\pi \times 2.35 \times 10^5 }\times \dfrac{(2.0115\times 10^{-3})^3-(2\times 10^{-3})^3}{3}\ A

I=68.31\times 10^{-6}\ A

7 0
2 years ago
Read 2 more answers
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